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Rudiy27
3 years ago
15

Find the smallest value of p, such that 36p is a perfect cube.

Mathematics
1 answer:
insens350 [35]3 years ago
7 0

Answer:

<h2>6 is the required answer.....</h2>
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Identify the maximum or minimum value, domain, and range of the graph of the quadratic function.
Virty [35]

Answer:

See below ~

Step-by-step explanation:

<u>Details of the graph of the quadratic equation</u>

  • Minimum value = <u>-1</u>
  • Domain : <u>all real numbers</u>
  • Range : <u>y ≥ -1</u>
5 0
3 years ago
What is the answer for number 7?
aivan3 [116]

Answer:

Step-by-step explanation:

x=30

m=abe=180

8 0
3 years ago
Please i suck at math lol 2.0
Salsk061 [2.6K]

Answer:

i- ;-;

Step-by-step explanation:

6 0
3 years ago
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Please help me with this
timama [110]

Answer:

m<1 = 45°  

m<2 = 76°

m<3 = 80°

Step-by-step explanation:

<u>Points to remember</u>

1). Vertically opposite angles are equal

2). Sum of angles of a triangles is 180°

<u>To find the measures of given angles</u>

From the figure we get,

m<1 = 45°   [Vertically opposite angles]

By using angle sum property <2 + 59 + 45 = 180

m<2 = 180 - 104

m<2 = 76°

Also m<1 + m<3 + 55 = 180

m<3 = 180 - (m<1 + 55)

 = 180 - (45 + 55)

 = 180 - 100

m<3 = 80°

5 0
3 years ago
Graph the system of inequalities to show all possible solutions.<br> {y&lt;3x-2<br> {y ≥ -x+3
Semmy [17]

Answer:

see attachment for graph

Step-by-step explanation:

< or > : dashed line

≤ or ≥ : solid line

< or ≤ : shade below the line

> or ≥ : shade above the line

<u>To graph the line y < 3x-2</u>

Rewrite the equation as: y = 3x - 2

Find two points on the line:

when x = 0,  y = 3(0) - 2 = -2  →  (0, -2)

when x = 3,  y = 3(3) - 2 = 7  →  (3, 7)

Plots the found points (0, -2) and (3, 7).

Draw a straight, dashed line through the points.

<u>To graph the line y ≥ -x + 3</u>

Rewrite the equation as: y = -x + 3

Find two points on the line:

when x = 0,  y = -(0) + 3 = 3  →  (0, 3)

when x = 3,  y = -(3) + 3 = 0  →  (3, 0)

Plots the found points (0, 3) and (3, 0).

Draw a straight, solid line through the points.

Shade above the solid line and below the dashed line to the right of where the two lines intersect.  <u>The shaded area is the area of all possible solutions</u>.

5 0
2 years ago
Read 2 more answers
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