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3 years ago

-3+4u=-31 solve for u

Mathematics

1 answer:

solniwko [45]3 years ago

8 0

Answer:

u = -7

Step-by-step explanation:

-3+4u=-31

Add 3 to each side

-3+3 +4u = -31+3

4u = -28

Divide each side by 4

4u/4 = -28/4

u = -7

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Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

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Answer:

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Step-by-step explanation:

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$\frac{dy}{dx}=12x+14$

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$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

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Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

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Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

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2 years ago

Round each number to the nearest whole number. What is the best estimate for the answer to 276.37 – 67.81? A. 209 B. 208.6

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A.209

<span>276.37 – 67.81 = 208.56
The 5 in .56 means round up.
This means 208.56 will turn into 209.</span>

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