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3 years ago

10

If sin (A + B) = 1 and cos (A - B) = 1, find A, B

1 answer:

Strike441 [17]3 years ago

4 0

Step-by-step explanation:

sin (A + B) = 1 =sin 90

A+B=90 equation 1

cos (A - B) = 1=cos 0

A-B=0 equation 2

add 1 and 2

2A=90 A=45

2B=90 B=45

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Answer:

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Step-by-step explanation:

From the way it is written, the $x$ is outside the square root. I will rewrite it as:

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Divide denominator and numerator by $\sqrt{3}$

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$x=\frac{\sqrt{ (\sqrt{105}+3 \sqrt{7})^2}}{\sqrt{12} }$

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Factor $\frac{7}{2}$

$\frac{7}{2} (4+\sqrt{15} )$

Therefore,

$x=\sqrt{\frac{7}{2} \left(4+\sqrt{15} \right)}$

$x=\sqrt{\frac{7(4+\sqrt{15})}{2}}$

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