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Darya [45]
3 years ago
7

How do you simplify (9x^8 y^3)^1/2

Mathematics
1 answer:
kondaur [170]3 years ago
7 0
\left(9x^8y^3\right)^\frac{1}{2}=\left(3^2x^8y^3\right)^\frac{1}{2}=\left(3^2\right)^\frac{1}{2}\cdot\left(x^8\right)^\frac{1}{2}\cdot\left(y^3\right)^\frac{1}{2}\\\\=3^{2\cdot\frac{1}{2}}\cdot x^{8\cdot\frac{1}{2}}\cdot y^{3\cdot\frac{1}{2}}=3^1\cdot x^4\cdot y^\frac{3}{2}=3x^4\cdot y^{1\frac{1}{2}}\\\\=3x^4\cdot y^{1+\frac{1}{2}}=3x^4\cdot y^1\cdot y^\frac{1}{2}=3x^4y\sqrt{y}
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3 tenths + 4 Tenths = __0.7____ tenths
vovangra [49]

Answer:

7 tenths

Step-by-step explanation:

3 tenths + 4 tenths = 3/10 + 4/10 = 0.3 + 0.4 = 0.7

= 7 tenths

6 0
2 years ago
In what time the compound amount of Rs 60000 at 10% rate is rs 79860?​
Ksenya-84 [330]

Answer:

P= Rs 60000

A= Rs 79860

T=1 & 1/2 year = 3/2 years

    = 3/2 x 2 = 3 half years

R= ?  

Applying the formula A= P (1+r/100)^T

           79860  = 60000 (1+ r/100)^3

                  79860/60000 = (1+r/100)^3

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root(3)(1331/1000) = (1+r/100)

                     11/10 = 1+r/100

                     11/10 -1 = r/100

                      1/10 = r/100

                       r= 10 %

Step-by-step explanation:

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3 years ago
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5 0
2 years ago
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2 years ago
A research team hypothesizes that setting weekly scheduled online interactions versus not setting such interactions can boost th
leva [86]

Answer:

Type I error occurs when the null hypothesis, H0, is rejected, although it is true.

Here the null hypothesis, H0 is:

H0: Setting weekly scheduled online interactions will boost the well being of people who are living on their own during the stay at home order.

a) A Type I error would be committed if the researchers conclude that setting weekly scheduled online interactions will not boost the well being of people who are living on their own during the stay at home order, but in reality it will

b) Two factors affecting type I error:

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