Answer:
A'(-3,0), B'(0,-3) and C'(4,7)
Step-by-step explanation:
We are given that the vertices of triangle are A(0,-3), B(3,0) and C(-7,4).
We have to find the coordinates of the image of triangle under a rotation of 90° clockwise about the origin.
90° clockwise about the origin
Rule:![(x,y)\rightarrow (y,-x)](https://tex.z-dn.net/?f=%28x%2Cy%29%5Crightarrow%20%28y%2C-x%29)
Using the rule
The coordinates of A'
![A(0,-3)\rightarrow A'(-3,0)](https://tex.z-dn.net/?f=A%280%2C-3%29%5Crightarrow%20A%27%28-3%2C0%29)
The coordinates of B'
![B(3,0)\rightarrow B'(0,-3)](https://tex.z-dn.net/?f=B%283%2C0%29%5Crightarrow%20B%27%280%2C-3%29)
The coordinates of C'
![C(-7,4)\rightarrow C'(4,7)](https://tex.z-dn.net/?f=C%28-7%2C4%29%5Crightarrow%20C%27%284%2C7%29)
Hence, the vertices of image of triangle is given by
A'(-3,0), B'(0,-3) and C'(4,7)
Answer:
110%
Step-by-step explanation:
3,927/3,570
=1.1
=110%
3/10 you go by how many decimal points to move over... 0.1 one tenth.. 0.01 one hundeth an soo on.
2n + 3 = 5
2n = 2
n = 1
the sum of 2 times a number and three means you add 2n + 3 and since it is equal to 5 you then solve for n.