3 years ago

Can someone help me please

Mathematics

1 answer:

Licemer1 [7]3 years ago

5 0

Answer:

21°

angles don't change in dilutions but lengths do

plssmark brainliesttt

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Solving the expression $\frac{4-5i}{2+3i}$ we get $-\frac{7}{13}-\frac{22i}{13}$

So, Option A is correct.

Step-by-step explanation:

We need to solve the expression: $\frac{4-5i}{2+3i}$

Multiplying and dividing by 2-3i

$=\frac{4-5i}{2+3i}*\frac{2-3i}{2-3i}\\=\frac{4-5i*2-3i}{2+3i*2-3i}\\=\frac{4(2-3i)-5i(2-3i)}{(2)^2-(3i)^2}\\=\frac{8-12i-10i+15i^2)}{4-9i^2}\\We\,\,know\,\, i^2=-1\\=\frac{8-12i-10i+15(-1)}{4-9(-1)}\\=\frac{8-15-12i-10i}{4+9}\\=\frac{-7-22i}{13}\\=-\frac{7}{13}-\frac{22i}{13}$

So, solving the expression $\frac{4-5i}{2+3i}$ we get $-\frac{7}{13}-\frac{22i}{13}$

So, Option A is correct.

Keywords: Complex numbers

Learn more about Complex numbers at:

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