Answer:
8.8 pounds
Step-by-step explanation:
There are 7 days in a week, so the daily loss was ...
(28 kg)/(7 days) = 4 kg/day
In pounds, that is about ...
(4 kg/day)(2.2 lb/kg) = 8.8 lb/day
Answer:
srry man i suck at civics, but i think it is B?
Step-by-step explanation:
The correct answers are:
- Wage/salary;
- Active job seekers;
The amount of money you earn by working is your wage or salary. The difference being that the wage represents the money you get paid on hourly, weekly, or monthly basis, while the salary is what you earn in year. The wages/salaries vary a lot, some being very high, some being modest, some very high, depending on the type of job, type of economy, as well as the qualifications of the worker.
The percentage of people that are actively looking for job is called active job seekers. The active job seekers can be people that are unemployed, but also people that re employed but want to work something or somewhere else. While some people struggle to find jobs and would accept almost anything, other people want to constantly progress, thus they are not satisfying with a job where they do not progress, so they seek for new challenges and opportunities.
Step-by-step explanation:
1. you set each expression equal to 0.
x-7=0 and x+3=0
2. Next you need to get the variable by itself so you would add 7 to both sides on the first equation and subtract 3 from both sides for the second one.
3. So your answers would be x=7 and x=-3. Those are the zeros.
![\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \stackrel{\textit{we'll use this one}}{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{2}{ h},\stackrel{-1}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=2\\ k=-1 \end{cases}\implies y=a(x-2)^2-1 \\\\\\ \textit{we also know that } \begin{cases} y=0\\ x=5 \end{cases}\implies 0=a(5-2)^2-1\implies 1=9a \\\\\\ \cfrac{1}{9}=a\qquad therefore\qquad \boxed{y=\cfrac{1}{9}(x-2)^2-1}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%5Ctextit%7Bparabola%20vertex%20form%7D%20%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllll%7D%20%5Cstackrel%7B%5Ctextit%7Bwe%27ll%20use%20this%20one%7D%7D%7By%3Da%28x-%20h%29%5E2%2B%20k%7D%5C%5C%5C%5C%20x%3Da%28y-%20k%29%5E2%2B%20h%20%5Cend%7Barray%7D%20%5Cqquad%5Cqquad%20vertex~~%28%5Cstackrel%7B2%7D%7B%20h%7D%2C%5Cstackrel%7B-1%7D%7B%20k%7D%29%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Cbegin%7Bcases%7D%20h%3D2%5C%5C%20k%3D-1%20%5Cend%7Bcases%7D%5Cimplies%20y%3Da%28x-2%29%5E2-1%20%5C%5C%5C%5C%5C%5C%20%5Ctextit%7Bwe%20also%20know%20that%20%7D%20%5Cbegin%7Bcases%7D%20y%3D0%5C%5C%20x%3D5%20%5Cend%7Bcases%7D%5Cimplies%200%3Da%285-2%29%5E2-1%5Cimplies%201%3D9a%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B1%7D%7B9%7D%3Da%5Cqquad%20therefore%5Cqquad%20%5Cboxed%7By%3D%5Ccfrac%7B1%7D%7B9%7D%28x-2%29%5E2-1%7D)
now, let's expand the squared term to get the standard form of the quadratic.
