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3 years ago

15

Police estimate that 25% of drivers drive without their seat belts. If they stop 6 drivers at random, find theprobability that m

ore than 4 are wearing their seat belts.

1 answer:

earnstyle [38]3 years ago

8 0

Answer:

%17.80

Step-by-step explanation:

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Amanda and Stephen wrote the following proofs to prove that vertical angles are congruent. Who is correct? Line segment NT inter

jolli1 [7]

In fact, both Amanda's and Stephen's profs are correct; they are just using different supplementary angles. Amanda's is using the supplementary angles <span>∠1 and ∠4, and</span> ∠3 and ∠4, whereas Stephen is using ∠1 and ∠2, and <span>∠2 and ∠3.</span><span> </span>Please check the picture to visualize this more effectively.

6 0

3 years ago

Read 2 more answers

What are the steps to answer 28=8b+13b-35

oksian1 [2.3K]

Let's solve this problem step by step.

28=8b+13b-35

Step 1: Bring 35 to 28.

28=8b+13b-35

+35 +35

63=8b+13b

Step 2: Add 8b and 13b.

63=21b

Step 3: Divide both sides by 21.

63/21=21b/21

So, the answer for this problem is 3=b.

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3 years ago

You spin a spinner with four numbers on it, and flip a coin. Find the probability of the compound event.

nikitadnepr [17]

Answer:

I think 4/7 but i'm not sure.

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

If the probability that your DVD player breaks down before the extended warranty expires is 0.034, what is the probability that

schepotkina [342]

Answer:

0.966

Step-by-step explanation:

Given that:

Probability of DVD player breaking down before the warranty expires = 0.034

To find:

The probability that the player will not break down before the warranty expires = ?

Solution:

Here, The two events are:

1. The DVD player breaks down before the warranty gets expired.

2. The DVD player breaks down after the warranty gets expired

In other words, the 2nd event can be stated as:

The DVD does not break down before the warranty gets expired.

The two events here, have nothing in common i.e. they are mutually exclusive events.

So, Sum of their probabilities will be equal to 1.

$\bold{P(E_1)+P(E_2)=1}\\\Rightarrow 0.034+P(E_2)=1\\\Rightarrow P(E_2)=1-0.034\\\Rightarrow P(E_2)=\bold{0.966}$

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3 years ago

At what angle does a diffraction grating produce a second-order maximum for light having a first-order maximum at 20.0 degrees?

hichkok12 [17]

Answer:

At 43.2°.

Step-by-step explanation:

To find the angle we need to use the following equation:

$d*sin(\theta) = m\lambda$

Where:

d: is the separation of the grating

m: is the order of the maximum

λ: is the wavelength

θ: is the angle

At the first-order maximum (m=1) at 20.0 degrees we have:

$\frac{\lambda}{d} = \frac{sin(\theta)}{m} = \frac{sin(20.0)}{1} = 0.342$

Now, to produce a second-order maximum (m=2) the angle must be:

$sin(\theta) = \frac{\lambda}{d}*m$

$\theta = arcsin(\frac{\lambda}{d}*m) = arcsin(0.342*2) = 43.2 ^{\circ}$

Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.

I hope it helps you!

6 0

3 years ago