I think the. answer is 511.2
Answer:
See verification below
Step-by-step explanation:
We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

Now, differentiate to obtain


To obtain the required form, extract a factor in both the numerator and denominator:

Answer: By 9.1%
Step-by-step explanation:
Answer:
17.95 :)
Step-by-step explanation:
25-78.85= 53.85, and 53.85/3= 17.95 so each pair of shorts costed 17.95
Answer:
The second one
Step-by-step explanation: