Calculate the minimum value of the quadratic f(X)=x^2-6x+10
1 answer:
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Answer:
50 units
Step-by-step explanation:
you use Pythagorean-theorem which means A^2+B^2 =C^2
It does not matter the order of A and B because it is adding. But C is the hypotenuse.
If we plug in the # this is what it looks like...
14^2 +48^2=C^2
or
48^2+14^2=C^2
14*14= 196
48*48=2,304
then you add
196+2,304=C^2
2,500= C^2
and you can use a calculator for this part you do 2,500
with the 2,500 you use the sign as in the picture and it gives you...
50
which means 50*50 = 2,500
Answer:
x = 4
Step-by-step explanation:
DE is parallel to AC and intersects the other 2 sides. It divides those sides proportionally, that is
=
, thus
=
( cross- multiply )
2(10 - x) = 3x ← distribute left side
20 - 2x = 3x ( subtract 3x from both sides )
20 - 5x = 0 ( subtract 20 from both sides )
- 5x = - 20 ( divide both sides by - 5 )
x = 4