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liq [111]
3 years ago
9

Calculate the minimum value of the quadratic f(X)=x^2-6x+10​

Mathematics
1 answer:
tangare [24]3 years ago
8 0
The answer is (-3,-1)
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Thanks for any help provided to my question! &lt;3<br>5m + 2(m + 8) + 3
disa [49]
5m+2(m+8)+3
5m+2m+16+3
7m+19
3 0
3 years ago
On a coordinate grid, point T is at (2, −4) and point S is at (2, 6). The distance (in units) between points T and S is ______.
-BARSIC- [3]
The answer is 10
This is because both points have the same x value, which is 2, which means the distance between them is a straight line. That means that we can simply find the distance between the y values, and -4 to 0 is 4 units, and 0 to 6 is 6 units, so 4 + 6 = 10.

I hope this helps!
6 0
3 years ago
Read 2 more answers
If 3x+y=14, and x and y are positive integers, all of the following could be the value of x+y EXCEPT? This is an sat question an
vodka [1.7K]
Possible values are 

x=1,y=11

x=2,y=8

x=3,y=5

x=4,y=2
8 0
3 years ago
The function f(x) varies inversely with x and f(x)=0.5 when x = 0.3. What is f(x) when x = 2.4? A)5.76 B)0.0625 C)0.30 D)0.15
goldfiish [28.3K]

Answer:

B) 0.0625

Step-by-step explanation:

f(x) = k / x

f(x)=0.5 when x = 0.3

f(x) = k / x

0.5 = k / 0.3

Cross product

0.5 * 0.3 = k

k = 0.15

What is f(x) when x = 2.4?

f(x) = k / x

f(x) = 0.15 / 2.4

f(x) = 0.0625

The answer is B) 0.0625

3 0
3 years ago
A red balloon starts at 7.3 meters off the ground and rises at 2.6 meters per second. A blue balloon starts at 12.4 meters off t
nexus9112 [7]
This problem is an example of solving equations with variables on both sides. To solve, we must first set up an equation for both the red balloon and the blue balloon. 

Since the red balloon rises at 2.6 meters per second, we can represent this part of the equation as 2.6s. The balloon is already 7.3 meters off of the ground, so we just add the 7.3 to the 2.6s: 

2.6s + 7.3

Since the blue balloon rises at 1.5 meters per second, we can represent this part of the equation as 1.5s. The balloon is already 12.4 meters off of the ground, so we just add the 12.4 to the 1.5:

1.5s + 12.4

To determine when both balloons are at the same height, we set the two equations equal to each other: 

2.6s + 7.3 = 1.5s + 12.4

Then, we solve for s. First, the variables must be on the same side of the equation. We can do this by subtracting 1.5s from both sides of the equation: 

1.1s + 7.3 = 12.4

Next, we must get s by itself. We work towards this by subtracting 7.3 from both sides of the equation: 

1.1s = 5.1

Last, we divide both sides by 1.1. So s = 4.63. 

This means that it will take 4.63 seconds for both balloons to reach the same height. If we want to know what height that is, we simply plug the 4.63 back into each equation: 

2.6s + 7.3
= 2.6 (4.63) + 7.3
= 19.33

1.5s + 12.4
= 1.5 (4.63) + 12.4
= 19.33

After 4.63 seconds, the balloons will have reached the same height: 19.33 meters.
6 0
3 years ago
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