1st quartile: 11
median: 38.50000
3rd quartile: 45
<h3>According to the given information:</h3>
- Order these numbers in increasing order: 6, 7, 15, 36, 41, 43, 47, 49
- There is a 38.5 median (it is the mean of 36 and 41 - the pair of middle entries).
- 6,7,15,36, or the left-most half of the data, make up the sample.
- The median of the lower half is 11, which is the first quartile (it is the mean of 7 and 15 - the pair of middle entries).
- 41, 43, 47, and 49, which are the data points in the upper half, are to the right of the median.
- The median of the upper half is 45 in the third quartile (it is the mean of 43 and 47 - the pair of middle entries).
- The biggest value deviates 10.5 from the median (49-38.5)
Measure descriptive statistics
1st quartile: 11
median: 38.50000
3rd quartile: 45
To know more about quartile visit:
brainly.com/question/8737601
#SPJ4
I understand that the question you are looking for is :
2 Drag the tiles to the boxes to form correct pairs. Match the values associated with this data set to their correct descriptions. {6, 47, 49, 15, 43, 41, 7, 36} first quartile 38.5 median 11 third quartile 10.5 the difference of the largest value and the median 45
Answer:
420 hg = __4200000___ cg
Step-by-step explanation:
<h2>please mark me brainliest</h2>
Answer:
(14a+3, 21+4) = 1
Step-by-step explanation:
We are going to use the Euclidean Algorithm to prove that these two integers have a gcd of 1.
gcd (14a + 3, 21a + 4) = gcd (14a+3, 7a + 1) = gcd (1, 7a+1) = 1
Therefore,
(14a + 3, 21a + 4) = 1
You can replace the h and w with 6 and 3 in the expression. Then the expression is 12*6+30*3=162 dollars. So the amount paid to this employee is 162 dollars.
Answer:
(-4, -3), (4, -1), (8, 0), (12, 1)
Step-by-step explanation:
The x- and corresponding y-values are listed in the table. Put each pair in parentheses, <em>x-value first</em>. (That is an <em>ordered pair</em>.)
(x, y) = (-4, -3) . . . . from the first table entry
(x, y) = (4, -1) . . . . from the second table entry
(x, y) = (8, 0) . . . . from the third table entry
(x, y) = (12, 1) . . . . from the last table entry