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Naddik [55]
2 years ago
13

3. John and Nelly are cleaning their house. Nelly takes 3 hours longer than John if she cleans the house alone. If they can do t

he cleaning together in 2 hours, how long can John clean all by himself?​
Mathematics
1 answer:
swat322 years ago
8 0

Answer:

1 hour?

Step-by-step explanation:

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What is 1 1/2 subtracted from the sum of 4 2/3 and 5 2/5
olchik [2.2K]

Answer:

7 9/10

Step-by-step explanation:

First, we need to add 4 2/3 and 5 2/5.

We should begin with converting the fractions into improper fractions.

4 2/3 + 5 2/5= 14/3 + 27/5

Now, we find the common denominator

= 70/15 + 71/15

We can add:

= 141/15

And simplify. 

= 9 2/5

Finally, we subtract 1 1/2 from 9 2/5

Your answer is 7 9/10. Hope this helps!

Please Mark Brainliest

7 0
2 years ago
Read 2 more answers
5m + 3 ( 8m +7 ) +4^2<br><br> Can someone help me
Pie

Answer:

29m+37?

Step-by-step explanation:

<em>Pemdas</em>

5m+3(8m+7)+4^2

Parentheses first: 5m+24m+21+4^2

Exponents next: 5m+24m+21+16

No multiplication or division so addition is last:

29m+37

These two can't add together because one has a variable.

7 0
3 years ago
What is the arc measure of BAD on circle P in degrees?
lianna [129]

Answer:

244

Step-by-step explanation:

74+42=116

360-116=244.

5 0
3 years ago
Please help will give brainliest. Links will be banned
AlexFokin [52]

Answer:

I believe it is C.

6 0
3 years ago
The diagram shows the sector of a circle with the centre O and radius 6cm.
cricket20 [7]

Answer:

Area of the shaded region = 1.92 cm²

Step-by-step explanation:

From the picture attached,

Area of the shaded region = Area of the sector OMN - Area of the triangle OMN

Area of sector OMN = \frac{\theta}{360}(\pi r^{2})

Here, θ = Central angle of the sector

r = radius of the sector

Area of sector OMN = \frac{50}{360}(\pi )(6)^2

                                  = 15.708 square cm

Area of ΔOMN = 2(ΔOPN)

Area of ΔOPN = \frac{1}{2}(OP)(PN)

Area of ΔOMN = OP × PN

In ΔOPN,

sin(25°) = \frac{PN}{ON}

PN = ONsin(25°)

     = 6sin(25°)

     = 2.536 cm²

cos(25°) = \frac{OP}{ON}

OP = ONcos(25°)

OP = 6cos(25°)

OP = 5.438 cm

Area of ΔOMN = 2.536 × 5.438

                         = 13.791 cm²

Area of the shaded region = 15.708 - 13.791 = 1.917 cm²

                                             ≈ 1.92 cm²

3 0
3 years ago
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