<span>625(5xy)^-3/ (5x)^2 y^7

625
= -------------------- / 25x^2y^7
125 x^3y^3

= 5/x^3y^3 / </span>25x^2y^7
= 5/x^3y^3 * (1/ 25x^2y^7)
= 1 / 5x^5y^10

answer

1
-----------------
5x^5y^10

3 0

3 years ago

The equation of the line with slope −4 that goes through the point (8,−3)

Korolek [52]

Answer:

y = -4x + 29

Step-by-step explanation:

-3 = -4(8) + b

-3 = -32+b

29=b

7 0

3 years ago

I need help plsss!!!!!!!!!

Zepler [3.9K]

Answer:

kne-hnfd-vsq

Step-by-step explanation:

join this link

5 0

2 years ago

A circle has the center of (1,-5) and a radius of 5 determine the location of the point (4,-1)

Sliva [168]

"determine the location" or namely, is it inside the circle, outside the circle, or right ON the circle?

well, we know the center is at (1,-5) and it has a radius of 5, so the distance from the center to any point on the circle will just be 5, now if (4,-1) is less than that away, is inside, if more than that is outiside and if it's exactly 5 is right ON the circle.

well, we can check by simply getting the distance from the center to the point (4,-1).

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \stackrel{center}{(\stackrel{x_1}{1}~,~\stackrel{y_1}{-5})}\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[4-1]^2+[-1-(-5)]^2}\implies d=\sqrt{(4-1)^2+(-1+5)^2} \\\\\\ d = \sqrt{3^2+4^2}\implies d =\sqrt{9+16}\implies d=\sqrt{25}\implies \stackrel{\textit{right on the circle}}{d = 5}$

5 0

3 years ago