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NeX [460]
3 years ago
14

Of the 12 temporary employees in a certain company, 4 will be hired as permanent employees. If 5 of the 12 temporary employees a

re women, how many of the possible groups of 4 temporary employees consist of 3 women and 1 man
Mathematics
1 answer:
Ivenika [448]3 years ago
8 0

Answer:

<h2>70 possible groups</h2>

Step-by-step explanation:

Given the total number of employee to be equal to 12 temporary employee.

Number of women employee = 5 women

Number of men employee = 12 - 5 = 7 men

If 4 will be hired as permanent employees, the possible ways they can be grouped so that the 4 temporary employees consists of 3 women and 1 man can be done by applying the combination formula.

Combination has to do with selection. For example, if r objects are to be selected from n pool of similar objects, this can be done in <em>nCr </em>different ways.

nCr = \frac{n!}{(n-r)!r!}

According to question, we are to select 3 women from 5 women and 1 man from 7 men. Based on similarity in sex, this can be done in (5C3* 7C1) different ways .

5C3 * 7C1\\=  \frac{5!}{(5-3)!3!} * \frac{7!}{(7-1)!1!}\\\\= \frac{5!}{2!3!} * \frac{7!}{6!1!}\\\\=  \frac{5*4*3!}{3!*2} * \frac{7*6!}{6!*1}\\\\= \frac{20}{2} * \frac{7}{1}\\  \\= 10*7\\\\= 70\ possible\ groups

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VMariaS [17]

Answer:

A. a = 60

B. x = 30

C. x = 70

D. a = 30

E. x = 190

Have a great evening!

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2 years ago
Let $a_1$, $a_2$, . . . , $a_{10}$ be an arithmetic sequence. If $a_1 + a_3 + a_5 + a_7 + a_9 = 17$ and $a_2 + a_4 + a_6 + a_8 +
vfiekz [6]

So

a be first term and d be common difference

  • a+a+2d+a+4d+a+6d+a+9d=17
  • 5a+21d=17--(1)

And

  • a+d+a+3d+a+5d+a+7d+a+9d=15
  • 5a+25d=15--(2)

Eq(1)-Eq(2)

  • -4d=-2
  • d=1/2

Put in second one

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2 years ago
EASY MATH!!! The formula F=9/5C+32 is used to convert Celsius to Fahrenheit temperature. A. Solve the formula for C B. The boili
puteri [66]

F=\dfrac{9}{5}C+32\\\\A.\\\dfrac{9}{5}C+32=F\ \ \ |-32\\\\\dfrac{9}{5}C=F-32\ \ \ |\cdot\dfrac{5}{9}\\\\C=\dfrac{5}{9}(F-32)



B.\\F=212\to C=\dfrac{5}{9}(212-32)=\dfrac{5}{9}\cdot180=100\\\\212^oF=100^oC



C.\\F=80\to C=\dfrac{5}{9}(80-32)=\dfrac{5}{9}\cdot48\approx26.7\\\\80^oF\approx26.7^oC

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3 years ago
Jeff and Ed are cimbing a small mountain. The height jeff cimbed with respect to time is given by the function H)=-250 |x - 4| +
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Answer:

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2 years ago
Please help me photo include
nikklg [1K]

Answer:

\frac{-117}{10}

Step-by-step explanation:

1) Change the mixed fractions into improper fractions:

-3\frac{1}{5} + (-8\frac{1}{2} )\\= \frac{-16}{5} - \frac{17}{2}

2) Multiply the first fraction by 2/2 and the second fraction by 5/5 in order to create common factors on the denominator (You can do this because you are essentially multiplying by one, for example 2/2 = 1):

\frac{-16}{5} *\frac{2}{2}  - \frac{-17}{2} * \frac{5}{5} \\ =\frac{-32}{10} - \frac{85}{10}

3) Simplify the numerator(top part) while keeping the denominator(bottom part) the same:

\frac{-32}{10} -\frac{85}{10}  \\\\=\frac{-32 - 85}{10}\\ \\= \frac{-117}{10}

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3 years ago
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