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maxonik [38]
3 years ago
15

The floor of a restaurant is a square of sides 28 cm. The floor covered with square tiles of sides 40 cm. Calculate the total nu

mber of tiled used.
Mathematics
1 answer:
andrew11 [14]3 years ago
5 0

Answer:

I'm going to calculate with sides 28 m

4,900 tiles used

Step-by-step explanation:

Area restaurant 28x28 = 784 m squared

each tile 40 cm = 0.4m

area of tile 0.4x0.4 =0.16

784/0.16 = 4,900

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Answer:

The answer would be B. To solve you would have to change each equation in to slope intercept from (y=mx+B).  

Step-by-step explanation:


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4 years ago
Prompt<br> Describe a simulation used to determine a game of darts.<br><br> Plzzzzz help???
UkoKoshka [18]

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5 0
3 years ago
3) Postcards: Marcie wants to make a box to hold her postcard collection from a piece of
klasskru [66]

The volume of the box is the amount of space in it.

The dimension of the postcard is:

\mathbf{Length = 10}

\mathbf{Width = 18}

Let x represents the length of the cut.

So, the dimension of the box is:

\mathbf{Length = 10 -2x}

\mathbf{Width = 18 -2x}

\mathbf{Height = x}

<u>(a) The function that represents the volume of the box</u>

This is calculated as:

\mathbf{V(x) = Length \times Width \times Height}

So, we have:

\mathbf{V(x) = (10 - 2x) \times (18 - 2x) \times x}

Expand

\mathbf{V(x) = 180x - 56x^2 + 4x^3}

Hence, the volume function is: \mathbf{V(x) = 180x - 56x^2 + 4x^3}

<u>(b) The dimension that maximizes the volume</u>

We have:

\mathbf{V(x) = 180x - 56x^2 + 4x^3}

Differentiate

\mathbf{V'(x) = 180- 112x + 12x^2}

Set to 0

\mathbf{180- 112x + 12x^2 = 0}

Using a calculator, we have:

\mathbf{x = 7.3,2.1}

The value x = 7.3 is greater than the dimension of the box.

So, we have:

\mathbf{x = 2.1}

Recall that:

\mathbf{Length = 10 -2x}

\mathbf{Width = 18 -2x}

\mathbf{Height = x}

So, we have:

\mathbf{Length = 10 -2 \times 2.1 = 5.8}

\mathbf{Width = 18 -2 \times 2.1 = 13.8}

\mathbf{Height = 2.1}

Hence, the dimension that maximizes the volume is 5.8 by 13.8 by 2.1

<u>(c) The maximum volume</u>

This is calculated as the product of the dimension of the box

So, we have:

\mathbf{Volume = 5.8 \times 13.8 \times 2.1}

\mathbf{Volume = 168.1}

Hence, the maximum volume of the box is 168.1 cubic inches

Read more about volumes at:

brainly.com/question/17056191

5 0
3 years ago
Select from the drop-down menus to correctly complete the proof.
tekilochka [14]

rational irrational irrational

7 0
3 years ago
Read 2 more answers
I need help please!!!
DIA [1.3K]
Alrighty, so to order the quantities from least to greatest as asked for in the question, first we should convert all the values given to a specific way of writing (this being either decimal, fraction or mixed number). Since all but one is given in decimal form, we can convert the other mixed number to be the same. 
An easy way to do this is by separating the mixed number from its corresponding fraction.
 3\frac{3}{8} becomes 3+ \frac{3}{8}
3+(3÷8)
You can long divide 3 and 8 to get 0.375
3+0.375 = 3.375

Now that all of the values are written in the same manner, order them from least to greatest. 
3.75, 3.375, 2.625, 3.5
2.626, 3.375, 3.5, 3.75

~I hope this helps!~
3 0
4 years ago
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