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Ivan
3 years ago
15

A high school band director has 120 students in his marching band. The marching band plays at all football games, so the band mu

st travel by school bus to each away game. The band director knows that each school bus holds 60 students. Which of the following best describes a method of assigning the band students to the two school buses so that each band student has a fair chance of being selected for either school bus? There is no way to assure that each band student has a fair chance of being selected for either bus. Randomly assign each student an unique number ranging from 1 to 120. Label colored balls with each number that is assigned to a student. Place all of the labeled balls into a bin, and randomly select 60 balls. The students with numbers found on the first 60 randomly selected balls will be assigned to the first school bus, and the remaining 60 students will be assigned to the second school bus. Using a random number generator, assign each band student a number, eliminating duplicate numbers. Assign each band student with a positive number to the first school bus, and assign each band student with a negative number to the second school bus. Using a random number generator, assign each band student a number, eliminating duplicate numbers. Assign each band student with an even number to the first school bus, and assign each band student with an odd number to the second school bus.
Mathematics
2 answers:
lidiya [134]3 years ago
4 0

Randomly assign each student an unique number ranging from 1 to 120. Label colored balls with each number that is assigned to a student. Place all of the labeled balls into a bin, and randomly select 60 balls. The students with numbers found on the first 60 randomly selected balls will be assigned to the first school bus, and the remaining 60 students will be assigned to the second school bus.

umka2103 [35]3 years ago
3 0
The first method is the best because 60+60=120 so either way even if you were picked randomly you will get a seat on the bus.
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Step-by-step explanation:

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3 years ago
Solve for n<br><br> -19=-8+n
laila [671]

-------------------------------------------------------------------------------------------------------------

Answer:  \textsf{n = -11}

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Given:  \textsf{-19 = -8 + n}

Find:  \textsf{Solve for n}

Solution: In order to solve for n we need to add 8 to both sides which would cancel -8 on the right side and isolate n giving us the value of n.

<u>Add 8 to both sides</u>

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Therefore, the final answer would be that n is equal to -11.

6 0
1 year ago
Read 2 more answers
part b is: if the energy release of one earthquake is 10,000 times that of another, how much larger is the Richter scale reading
kotegsom [21]

You could use the information from part A to get B. I'm not sure if you want A or not, so I'll do it as well.

A

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E = 2 * 10^15

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M = 2/3 * log (2 * 10^15/10^(4.4) )

M = 2/3 * log( 7.9621* 10^10)

M = 2/3 * 10.901

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Part B

Suppose that you use Eo and your base. Eo is 10^4.4

Now the new earthquake is E = 10000 * Eo

So what you get now is M = (2/3)* Log(10000 * Eo / Eo )

The Eo's cancel out.

M = 2/3 * log(10000)

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M = 2.6667 difference in the Richter Scale Reading. It is still an awful lot of energy.

What this tells you is that if the original reading was (say) 6 then the 10000 times bigger reading would 8.266667

Answer: M = 2.6667


8 0
3 years ago
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Shkiper50 [21]

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add 6 per every number till you get to the 94th term

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