Answer:
4455587111*#654..++4756##8008/+.+=///=!558887425
Let x = the cost of the student discount card.
x + the cost of the passes = 29.50
x + 15(1.50) = 29.50
x + 22.50 = 29.50
Subtract 22.50 on both sides to isolate the variable x.
x = 29.50 - 22.50
x = 7
The student discount card is $7.
The percentage increase is 78.68% for your correct answer
The answer is the third option
Answer:
85.29%
Step-by-step explanation:
We know 18 televisions sets contains 3 defective sets => 15 TV sets are ok
So the total number of possible ways for the hotel to buy = 
At least one of the defective sets, so we need to find the probability for 1 defective sets, 2 defective sets and 3 defective sets.
1. The number of ways the hotel purchases 8 of these televisions sets but have 1 defective one:
P(1) =
*
= 6435*3 = 19305
2. The number of ways the hotel purchases 8 of these televisions sets but have 2 defective one:
P(2) =
*
= 5005*3= 15015
3. The number of ways the hotel purchases 8 of these televisions sets but have 3 defective one:
P(3) =
*
= 3003*1 = 3003
So the probability that the hotel receives at least one of the defective sets =
(P(1) + P(2) + P(3) ) / P = (19305 +15015 + 3003 ) / 43785*100% = 85.29%