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egoroff_w [7]
3 years ago
10

Express (16^3)^1/2 in simplest radical form.

Mathematics
1 answer:
Rufina [12.5K]3 years ago
6 0

Answer:

I assume you mean 16^(1/3) i.e. the cube root of 16

I am also assuming you mean the real cube root because, as you may know, every non-zero real number has three cube root - one real and two complex conjugates.

Since 16 = 8 x 2 and 8 = 2³ then (2³ x 2)^1/3 = (2³)^1/3 x 2^1/3 = 2 x 2^1/3

You might check that the cube root of 16 is about 2.52 which is twice the cube root of 2

Step-by-step explanation:

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IMPORTANT! WILL VOTE BRAINLIEST!!!
nikdorinn [45]

Answer:

The value of the ve = 9m/sec

Step-by-step explanation:


From the given formula, it can be conclude that this is evenly accelerated movement.

First I will rewrite given formula

vi = √ ve∧2 - 2ad   First we will square on both sides and get

vi∧2 = ve∧2 - 2ad Now we will add monom (+2ad) to both sides and get

vi∧2 + 2ad = ve∧2 -2ad + 2ad =>

ve∧2 = vi∧2 +2ad  Now we will rooted both sides and get

ve = √vi∧2 + 2ad  

Now we will replace given data vi=7m/sec, a=8m/s∧2 and d=2m in the last formula

ve= √7∧2 + 2*8*2 = √49+32 = √81 = 9

ve= 9m/sec

Good luck!!!



7 0
3 years ago
There are 31 motor scooters on a used car lot, along with 67 other vehicles.
just olya [345]

Answer:

31/98

Step-by-step explanation:

31 motor scooters

67 other vehicles

31 + 67 total vehicles

31 + 67 = 98

The probability is motor scooters/total vehicles

31/98 is the answer.

4 0
3 years ago
33. A competition question requests students to form a three-digit number.
aniked [119]

Answer:

  532

Step-by-step explanation:

  532 = 2·2·7·19

__

There are 24 possible 3-digit numbers from the set {2, 3, 5, 7}. Of those, 6 have four factors: 372, 375, 532, 572, 732, 735.

The sums of factors of these numbers are ...

  38, 18, 30, 28, 68, 22

The number of interest is 532.

7 0
3 years ago
What is 4.2e+16 written out?
worty [1.4K]
42000000000000000



....................
4 0
3 years ago
A sample of 11 students using a Ti-89 calculator averaged 31.5 items identified, with a standard deviation of 8.35. A sample of
lina2011 [118]

Answer:

We reject H₀, with CI = 90 % we can conclude that the mean numbers of times identified with Ti-84 does not exceed that of the Ti-89 by more than 1,80

Step-by-step explanation:

Ti-89 Calculator

Sample mean     x = 31,5

Sample standard deviation   s₂  = 8,35

Sample size        n₂ = 11

Ti-84 Calculator

Sample mean     y = 46,2

Sample standard deviation   s₁  = 9,99

Sample size        n₁ = 12

t(s)  = ( y - x - d ) / √s₁²/n₁ + s₂²/n₂

t(s)  = 12,9 / √(99,8/12) + (69,72/11)

t(s)  = 12,9 / √8,32 + 6,34

t(s)  = 12,9 / 3,83

t(s) = 3,37

Test Hypothesis

Null Hypothesis               H₀      y - x > 1,80

Altenative Hypothesis       Hₐ      y - x ≤ 1,80

We have a t(s) = 3,37

We need to compare with t(c)   critical value for

t(c) α; n₁ +n₂-2            df = 12 +11 -2     df  = 21

If we choose  CI = 95 %    then  α = 5 %   α = 0,05

From t-student table

t(c) = 1,72

t(s) = 3,37

t(s) >t(c)

t(s) is in the rejection region therefore we accept Hₐ with CI = 95 %

8 0
3 years ago
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