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Igoryamba
4 years ago
5

A certain aircraft can fly 798 miles with the wind in 3 hours and travel the same distance against the wind in 7 hours. What is

the speed of the wind?
How do I set up the equations?
Mathematics
1 answer:
Vesnalui [34]4 years ago
7 0

Answer:

76 mph

Step-by-step explanation:

Let x mph be the speed of the aircraft and y mph be the speed of the wind.

<u>With the wind:</u>

Distance = 798 miles

Time = 3 hours

Speed = x + y mph

Then

3(x+y)=798\\ \\x+y=266

<u>Against the wind:</u>

Time = 7 hours

Speed = x - y mph

Then

7(x-y)=798\\ \\x-y=114

Add these two equations:

x+y+x-y=266+114\\ \\2x=380\\ \\x=190\ mph

Subtract these two equations:

(x+y)-(x-y)=266-114\\ \\x+y-x+y=152\\ \\2y=152\\ \\y=76\ mph

The speed of the aircraft is 190 mph, the speed of the wind is 76 mph

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Step-by-step explanation:

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Generally theta is written in radians and omega is written in radians per second. Now, since the revolutions are directly related to the radians and they want us to write our answer in revolutions, we can directly use the provided speeds in the formula, so we can rewrite it as:

n=(\frac{f_{f}+f_{0}}{2})t

where n represents the number of revolutions and f is the frequency at which the basket is turning.

The movement of the cylindrial basket can be split in two stages, when it accelerates and when it decelerates. So let's analye the first stage:

n=(\frac{4rev/s+0}{2})(9s)=18rev

and now let's analyze the second stage, where it decelerates, so we get:

n=(\frac{0rev/s+4rev/s}{2})(13s)=26rev

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Answer:

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Step-by-step explanation:

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Substitute into the formula;

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Answer:

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