Rhombus, Parallelogram, Kite, Rectangle, Square, Trapezoid, Isosceles Trapezoid
Find the area of the CD. (I used P for pi, too lazy @
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A=Pr² - Pr²
radius of the small hole in the middle, 0.75cm
radius of the CD, 6cm
A=3.14*6²-3.14*0.75²
A=111.27375cm²
The Approximate area of the CD is 111.27cm²
Let us first write down the given equation.
80 = 3y + 2y + 4 + 1
80 = 5y + 5
80 - 5 = 5y
75 = 5y
Just reversing both sides we get
5y = 75
Now dividing both sides by 5 we get
y = 15
So the value of y is 15.
I hope the procedure for solving the problem is clear to
you. In future you can solve such problems with ease following the procedure
described.
The answer to this question is -21
Answer:
17 units
Step-by-step explanation:
Given 2 congruent chords in the circle, then they are equidistant from the centre and perpendicular
There is a right triangle formed by legs 15 and 8, with radius r being the hypotenuse.
Using Pythagoras' identity in this right angle
r² = 15² + 8² = 225 + 64 = 289 ( take the square root of both sides )
r = 
= 17
