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3 years ago

F 1 /2 an apple was shared equally among the 3 people, what fraction of the whole apple did each person receive?

Mathematics

1 answer:

Luden [163]3 years ago

7 0

1/6 because 1/3 of 1/2 is 1/6

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PLEASE HELP!!!<br> HSJSHGXDBSJHCBDSHDCB PLEASEE

KatRina [158]

Answer:

the answer is 30

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2 years ago

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ZanzabumX [31]

Answer:

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Step-by-step explanation:

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3 years ago

Please help me!<br> Hint: the number is negative

wel

Answer:

$-36$ goes into the box

Step-by-step explanation:

Let the number be $x$ , then

$(m^x)^{\frac{1}{3}}=m^{-12}$

We now use the following property of exponents to simplify the left hand side of the equation.

$(a^m)^n=a^{mn}$

This implies that;

$m^{x\times \frac{1}{3}}=m^{-12}$

$\Rightarrow m^{\frac{x}{3}}=m^{-12}$

Since the bases are the same, we equate the exponents to get;

${\frac{x}{3}=-12$

We now multiply both sides by 3 to get;

$\frac{x}{3}\times 3=-12\times 3$

$\Rightarrow x =-36$

Therefore the number that goes into the box is $-36$

6 0

2 years ago

Points E, D, and H are the midpoints of the sides of ΔTUV. UV=56, TV=72, and HD=56. Find HE.

natita [175]

We need a diagram to do this

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3 years ago

A see-saw is 25 feet long with a fulcrum in the middle of the board. If a 60 lb. child sits three feet from the fulcrum, what is

My name is Ann [436]

Answer:

14.4 lb

Step-by-step explanation:

In a see-saw in equilibrium, the torque generated by one side needs to be the same generated in the other side. The torque is calculated by the product between the mass and the distance to the center of the see-saw.

The torque generated by the child is:

T1 = 60 * 3 = 180 lb*feet

So, the torque generated by the weight needs to be higher than T1 in order to lift the child.

The lowest mass is calculated when the mass is in the maximum distance, that is, 12.5 feet from the center.

So, we have that:

T2 = 180 = mass * 12.5

mass = 180/12.5 = 14.4 lb

So the lowest weight is 14.4 lb

4 0

3 years ago