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Lesechka [4]
3 years ago
14

For a normal curve with mean 7 and standard deviation 4, which of the following parts of the normal curve will have an area of a

pproximately 68%?
Mathematics
1 answer:
s2008m [1.1K]3 years ago
8 0
Becauser its really really really curvy and stuff i think that swhy ty
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Match the correct y=mx+b equation tot he graph<br><br> show explanation please
mr Goodwill [35]

Answer:

y=-x+3

Step-by-step explanation:

y=-x+3

you can see the negative slope in the direction

the +3 comes from the 3 in the x and y intercepts

m=-1

3 0
2 years ago
I need to know them from least to greatest
RSB [31]
- 3/10 = -0.3

order from least to greatest
-0.6, -3/10 and 3/5
3 0
2 years ago
Read 2 more answers
Find 3 different fraction equivalent to 8/9
Solnce55 [7]
Three fractions that are equivalent to 8/9 are 16/18, 24/27, and 32/36. 

Best of luck, friend. 
3 0
3 years ago
Read 2 more answers
How many solutions are there to the equation shown below? Explain your answer.*
bazaltina [42]

Answer:

  an infinite number

Step-by-step explanation:

The equation simplifies to ...

  12x -7 = 6x +10 +6x -17 . . . eliminate parentheses

  12x -7 = 12x -7  . . . . . . . .  collect terms

  0 = 0 . . . . subtract (12x-7) from both sides

This is true for all values of x. There are an infinite number of solutions.

3 0
3 years ago
) How many degrees of freedom are available for hypothesis tests and confidence intervals for single regression coefficient
sladkih [1.3K]

Answer:

We use students' t distribution therefore degrees of freedom is v= n-2

Step-by-step explanation:

<u>Confidence Interval Estimate of Population Regression Co efficient β.</u>

To construct the confidence interval for β, the population regression co efficient , we use b, the sample estimate of β. The sampling distribution of b is normally distributed with mean β and a standard deviation σ.y.x / √(x-x`)². That is the variable z = b - β/σ.y.x / √(x-x`)² is a standard normal variable. But σ.y.x  is not known so we use S.y.x and also student's t distribution rather than normal distribution.

t= b - β/S.y.x / √(x-x`)² = b - β/Sb    [Sb = S.y.x / √(x-x`)²]

with v= n-2 degrees of freedom.

Consequently

P [ - t α/2<  b - β/Sb  < t α/2] = 1- α

or

P [ b- t α/2 Sb<   β  < b+ t α/2 Sb] = 1- α

Hence a 100( 1-α) percent confidence for β the population regression coefficient for a particular sample size n <30  is given by

b± t α/2 Sb

Using the same statistic a confidence interval for α can be constructed in the same way for  β  replacing  a with b and Sa with Sb.

a± t α/2 Sa

Using the t statistic  we may construct the confidence interval for U.y.x for the given value X0 in the same manner

Y~0 ± t α/2(n-2) SY~

Y~0= a+b X0

4 0
3 years ago
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