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Andru [333]
2 years ago
7

8. Order the expressions from least to greatest. V31,0, (V24 + 2), V90

Mathematics
1 answer:
algol [13]2 years ago
5 0

Answer:

29/9, \sqrt[3]{90},  \sqrt{31}, (\sqrt{24}+2)

Step-by-step explanation:

Convert to decimal values and compare:

29/9           3.222222222

cube root 90   4.481404747

sqrt31            5.567764363

(sgrt24 + 2)    6.898979486

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Your doctor told you to eat 25 grams of fiber each day. You had 66 grams of fiber for breakfast. What percent of the 25 grams of
oksano4ka [1.4K]
To answer the question, divide the amount of fiber taken during breakfast by the total allowable amount then multiply by 100%. This gives us,

                                 (66 / 25) x 100% = 264 %

Thus, the answer is 264%. The answer clearly shows that the fiber taken so far is much more than the total allowable fiber intake. 
6 0
3 years ago
A model for the population in a small community after t years is given by P(t)=P0e^kt.
LUCKY_DIMON [66]
\bf \textit{Amount of Population Growth}\\\\
A=Ie^{rt}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\\
r=rate\to r\%\to \frac{r}{100}\\
t=\textit{elapsed time}\\
\end{cases}

a)

so, if the population doubled in 5 years, that means t = 5.  So say, if we use an amount for "i" or P in your case, to be 1, then after 5 years it'd be 2, and thus i = 1 and A = 2, let's find "r" or "k" in your equation.

\bf \textit{Amount of Population Growth}\\\\
A=Ie^{rt}\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &2\\
I=\textit{initial amount}\to &1\\
r=rate\\
t=\textit{elapsed time}\to &5\\
\end{cases}
\\\\\\
2=1\cdot e^{5r}\implies 2=e^{5r}\implies ln(2)=ln(e^{5r})\implies ln(2)=5r
\\\\\\
\boxed{\cfrac{ln(2)}{5}=r}\qquad therefore\qquad \boxed{A=e^{\frac{ln(2)}{5}\cdot t}} \\\\\\
\textit{how long to tripling?}\quad 
\begin{cases}
A=3\\
I=1
\end{cases}\implies 3=1\cdot e^{\frac{ln(2)}{5}\cdot t}

\bf 3=e^{\frac{ln(2)}{5}\cdot t}\implies ln(3)=ln\left( e^{\frac{ln(2)}{5}\cdot t} \right)\implies ln(3)=\cfrac{ln(2)}{5} t
\\\\\\
\cfrac{5ln(3)}{ln(2)}=t\implies 7.9\approx t

b)

A = 10,000, t = 3

\bf \begin{cases}
A=10000\\
t=3
\end{cases}\implies 10000=Ie^{\frac{ln(2)}{5}\cdot 3}\implies \cfrac{10000}{e^{\frac{3ln(2)}{5}}}=I
\\\\\\
6597.53955 \approx I
3 0
3 years ago
A store owner buys cell phones for $40 and marks up the price by 20%. Explained how to find the price at which she sells the cel
Gala2k [10]
Well depending on how you look at you could do $40 plus that extra 20% and since you said that means to add you would do the same price. as the actual price before you add that thirty 20% so you would add 40 plus 40 equals 80. If you did 25% the you would add 40 and 40 which is 80 and that's 20%out of 25% and add 5 to 80 and you get $85.
5 0
3 years ago
Find the general solution of (x+3)y’=2y
gregori [183]

Answer:

y=C(x+3)^2

Step-by-step explanation:

We are given:

\displaystyle (x+3)y^\prime=2y

Separation of Variables:

\displaystyle \frac{1}{y}\frac{dy}{dx}=\frac{2}{x+3}

So:

\displaystyle \frac{dy}{y}=\frac{2}{x+3} \, dx

Integrate:

\displaystyle \int\frac{dy}{y}=\int\frac{2}{x+3}\, dx

Integrate:

\displaystyle \ln|y|=2\ln|x+3|+C

Raise both sides to e:

|y|=e^{2\ln|x+3|+C}

Simplify:

|y|=(e^{\ln|x+3|})^2\cdot e^C

So:

|y|=C|x+3|^2

Simplify:

y=\pm C(x+3)^2=C(x+3)^2

5 0
3 years ago
Make r the subject of the formula
zloy xaker [14]

Answer:

r=\frac{-a+p}{a+p}

Step-by-step explanation:

-pr+p=ar+a

-ar-pr+p=a

-ar-pr=a-p

r(-a-p)=a-p

r=\frac{-a+p}{a+p}

3 0
3 years ago
Read 2 more answers
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