Answer:
39
Step-by-step explanation:
detailed explanation showed in the diagram above
The local minimum of function is an argument x for which the first derivative of function g(x) is equal to zero, so:
g'(x)=0
g'(x)=(x^4-5x^2+4)'=4x^3-10x=0
x(4x^2-10)=0
x=0 or 4x^2-10=0
4x^2-10=0 /4
x^2-10/4=0
x^2-5/2=0
[x-sqrt(5/2)][x+sqrt(5/2)]=0
Now we have to check wchich argument gives the minimum value from x=0, x=sqrt(5/2) and x=-sqrt(5/2).
g(0)=4
g(sqrt(5/2))=25/4-5*5/2+4=4-25/4=-9/4
g(-sqrt(5/2))=-9/4
The answer is sqrt(5/2) and -sqrt(5/2).
Answer:
The answer would be A. 3.3x
Step-by-step explanation:
3.3x can be broken down as 3.3.x
3.3 equals 9 and the 'x' is multiplied to 9.
Hence, it equals to 9x.
Find the factors of 16 and -24
16 = 8 x 2
-24 = 8 x -3
Note that both terms have "a" in it. Factor a out too
Answer:
8a(2 - 3b)
hope this helps
