We can solve the problem by using the basic relationship between space (S), time (t) and velocity (v) of the uniform motion:
The duration of the first part of the trip is
And the velocity is
So we can find the distance covered during the first part of the trip by rearranging the previous equation:
The duration of the second part of the trip is 15 minutes (because the duration of the total trip is 30 minutes, and the duration of the first part is 15 minutes), so
and the velocity is
Therefore, the distance covered in this second part of the trip is
So, the total distance between the home and the school is
Answer:
A) T = 95.12 N, B) L_man - 0.59 L
Explanation:
A) For this problem we must use the equilibrium, translational and rotational equations
∑τ = 0
Let's fix our reference system at the top of the stairs, the anti-clockwise rotation is positive
W x/2 + W_man x_man - T y = 0 (1)
Let's look with trigonometry for distances
cos 52 = x / L
x = L cos 52
sin 52 = y / L
y = L sin52
The man indicates it is at L / 3, so its distance is
x_man = L/3 cos 52
We replace
W L/2 cos 52 + W_man L/3 cos 52 - T L sin 52 = 0
T = cos 52 (W / 2 + W_man / 3) / sin 52
T = cos 52 (137/2 + 16.3 9.8 / 3) / sin 52
T = 121.75 ctan 52
T = 95.12 N
B) let's look for the maximum distance (x) that can be before breaking the rope
L_man = (-W L / 2 cos 52 + T L sin 52) / W_man cos 52
L_man / L = (-W / 2 ctan 52 + T tan 52) / W_man
L_man / L = ( -137/2 ctan 52 + 116 tan 52) / (16.3 9.8)
L_man / L = (-53.518 +148.47) /159.74
L_ma / L = 0.594
The man then climb a length of 0,59 (59%) along the length of the stairs
Answer:
Weight
a) weight's vertical component = Normal upward force
b) weight's horizontal component = Friction force = (mass of ball)(acceleration)
These forces depend upon the track,
1) inclined or horizontal
2) steepness.
Explanation
The force of gravity points straight down, but a ball rolling down a ramp doesn't go straight down, it follows the ramp. Therefore, only the component of the weight which points along the direction of the ball's motion can accelerate the ball.
weight's horizontal component = Friction force = (mass of ball)(acceleration)
The other component pushes the ball into the ramp, and the ramp pushes back.
If the ramp is horizontal, then the ball does not accelerate, as gravity pushes the ball into the ramp and not along the surface of the ramp. Hope this helps. Can u give me brainliest
Explanation:
To show motion on a graph you draw the path of where the object has gone
The testicles or testes balls they produce sperm.
It also produce hormones