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3 years ago

Una hormiga avanza 39 mm en un tiempo de 38s ,deternima la rapidez de la hormiga

1 answer:

4 0

Bueno deberias dividir 39 en 38 para obtener tu resultado, de esta forma sabras que la hormiga avanza 1.0263157895 (o en forma redondeada 1.03) esto significa que la hormiga corre 1.03 mm en 1 segundo, esto deria tu resultado

well to get the answer of this you have to divide 39 by 38 to obtain your asnwer, in this way you will know that the ant travels the speed f 1.0263157896(or in a rounded form 1.03) this means that the ant runs 1.03mm in 1 minute, this should be your result.

Hope this helps

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For fully developed laminar pipe flow in a circular pipe, the velocity profile is u(r) = 2(1-r2 /R2 ) in m/s, where R is the inn

sdas [7]

Answer:

a) $v_{max} = 2\ \textup{m/s}$

b) $v_{avg} = 1\ \textup{m/s}$

c) Q = 1.256 × 10⁻³ m³/s

Explanation:

Given:

The velocity profile as:

$u(r) = 2(1-\frac{r^2}{R^2} )$

Now, the maximum velocity of the flow is obtained at the center of the pipe

i.e r = 0

thus,

$v_{max}=u(0) = 2(1-\frac{0^2}{R^2} )$

$v_{max} = 2\ \textup{m/s}$

Now,

$v_{avg} = \frac{v_{max}}{2}\ \textup{m/s}$

$v_{avg} = \frac{2}}{2}\ \textup{m/s}$

$v_{avg} = 1\ \textup{m/s}$

Now, the flow rate is given as:

Q = Area of cross-section of pipe × $v_{avg}$

Q = $\frac{\pi D^2}{4}\times v_{avg}$

Q = $\frac{\pi 0.04^2}{4}\times 1$

Q = 1.256 × 10⁻³ m³/s

7 0

3 years ago

A locomotive is pulling 15 freight cars, each of which is loaded with the same amount of weight. The mass of each freight car (w

VMariaS [17]

Answer:

298,220 N

Explanation:

Let the force on car three is T_23-T_34

Since net force= ma

from newton's second law we have

T_23-T_34 = ma

therefore,

T_23-T_34 = 37000×0.62

T_23= 22940+T_34

now, we need to calculate

T_34

Notice that T_34 is accelerating all 12 cars behind 3rd car by at a rate of 0.62 m/s^2

F= ma

So, F= 12×37000×0.62= 22940×12= 275280 N

T_23 =22940+T_34= 22940+ 275280= 298,220 N

therefore, the tension in the coupling between the second and third cars

= 298,220 N

3 0

3 years ago

Calculate the work done by a 47N force pushing a pencil against a force of 23 N

stira [4]

I believe the answer would be 24N
Explanation: Because the forces are going against each other, in order to calculate the work done we need to subtract them. 47-23=24

8 0

2 years ago

The soymilk is most likely a ____.

denpristay [2]

If you're referring to this question :

A container of soymilk has the instruction on its label to "shake well before opening." The soymilk is most likely a !suspension!

Suspension is the answer.

Hope this helps,

Davinia.

4 0

3 years ago

Jayne lifts the barbell 120 cm upwards. She has a mass of 60kg. How much work does she do?

Rasek [7]

Work = Force x displacement
Force = mass x gravitational acceleration
Force = 60 x 9.81 = 588.6N
Work = 588.6 x 0.12m =70.632 J

3 0

3 years ago