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never [62]
3 years ago
14

Una hormiga avanza 39 mm en un tiempo de 38s ,deternima la rapidez de la hormiga

Physics
1 answer:
quester [9]3 years ago
4 0
Bueno deberias dividir 39 en 38 para obtener tu resultado, de esta forma sabras que la hormiga avanza 1.0263157895 (o en forma redondeada 1.03) esto significa que la hormiga corre 1.03 mm en 1 segundo, esto deria tu resultado

well to get the answer of this you have to divide 39 by 38 to obtain your asnwer, in this way you will know that the ant travels the speed f 1.0263157896(or in a rounded form 1.03) this means that the ant runs 1.03mm in 1 minute, this should be your result. 

Hope this helps
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What are the requirements for chemical labels
yaroslaw [1]

A chemical label should include: a product identifier, signal word, hazard statement, precautionary statement,pictorgrams and supplier information

Explanation:

The product identifier : positioned at the upper left end corner of the label gives the identity of the hazardous chemical by appropriate terms. i.e. the name and code

Signal word: The "Danger" and "WARNING" words. The former is used for a more severe hazard where as the former is for a less severe hazard

Hazard statement : gives a description of the nature and degree of hazard of the chemical

Precautionary statements : Put for workers and users on ways to minimize exposure and lower risks in event of contact with the harmful chemical

Supplier information : It has the chemical manufacturer details such as name, location and telephone number.

Pictograms : Normally symbols with red borders for visual illustration of the hazard chemical.

Learn More

Chemical labels : brainly.com/question/3115518

Keywords : chemical, labels

#LearnwithBrainly

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4 years ago
Which one of these is a chemical change?
satela [25.4K]
Burning a log because you are turning the log into ash from wood.
3 0
4 years ago
Read 2 more answers
What rule should be used to transform a table of data to represent the
adoni [48]

Answer:

Multiply the x values with -1.

Explanation:

By multiplying the numbers by one, you are changing them to be the opposite of their original state.

You multiply the numbers that are in the x-value column because you are reflecting the image over the y-axis.

<em>Hope this helped and good luck!</em>

4 0
3 years ago
A 85-kg physics student jumps from a dock into a 135 kg boat that is at rest by the dock. If the velocity
Gnesinka [82]

Answer:

<em>The final velocity of the student and the boat is 1.66 m/s</em>

Explanation:

<u>Law Of Conservation Of Linear Momentum </u>

The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is P=mv. If we have a system of bodies, then the total momentum is the sum of them all

P=m_1v_1+m_2v_2+...+m_nv_n

Let's call m_s = 85\ kg the mass of the physics student, m_b = 135\ kg the mass of the boat, v_{so} =4.3\ m/s the initial speed of the student, v_{bo} =0 the initial speed of the boat, v_f the final speed of both, assumed common since they keep joined after the jump. Applying the law of conservation of momentum, being P_o\ and\ P_f the initial and final momentum of the system, we have

P_o=P_f

m_sv_{so}+m_bv_{bo}=(m_s+m_b)v_f

Solving for v_f

v_f=\frac{m_sv_{so}+m_bv_{bo}}{(m_s+m_b)}

v_f=\frac{85(4.3)+0}{(85+135)}

v_f=1.66 \ m/s

The final velocity of the student and the boat is 1.66 m/s

4 0
4 years ago
Jupiter's moon Io has active volcanoes (in fact, it is the most volcanically active body in the solar system) that eject materia
Anton [14]

Answer:

91.64 km

91.64 km high material would go on earth if it were ejected with the same speed as on Io.

Explanation:

According to Newton Law of gravitation:

g=\frac{Gm}{r^2}

Where:

G is gravitational constant=6.67*10^{-11} m^3/kg.s^2

For Moon lo g is:

g_M=\frac{6.67*10^{-11}*8.93*10^{22}}{(1821*10^3)^2m^2} \\g_M=1.7962 m/s^2

According to law of conservation of energy

Initial Energy=Final Energy

K.E_i+mgh_i=K.E_f+mgh_f

\frac{1}{2}m(v_0)^2+mgh_o= \frac{1}{2}m(v_f)^2+mgh_f\\At\ maximum\ height\ v_f=0\\\frac{1}{2}m(v_0)^2+0=mgh_f\\v_0=\sqrt{2gh_f}

For Jupiter's moon Io:

Velocity is given by:

v_0_M=\sqrt{2g_Mh_f_M}

For Earth Velocity is given by:

v_0_E=\sqrt{2g_Eh_f_E}

Now:

v_o_M=v_o_E

\sqrt{2g_Mh_f_M}=\sqrt{2g_Eh_f_E}\\h_f_E=\frac{g_Mh_f_M}{g_E}

g_E=9.8 m/s^2

g_m=1.7962 m/s^2, As\ Calculated\ above

h_f_E=\frac{1.7962*500*10^3m}{9.8} \\h_f_E=91642.85 m\\h_f_E=91.64Km

91.64 km high material would go on earth if it were ejected with the same speed as on Io.

8 0
4 years ago
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