The answer is true
Step by step explanation:
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Answer:</h3>
4 m/s²
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Explanation:</h3>
From the question, we are given;
- Mass of the ball is 2.0 kg
- Acceleration of the ball is 4.2 m/s²
With the above information, we can calculate the force applied to the ball.
- From the second newton's law of motion, F = ma
- Therefore;
Net force, F = 2.0 kg × 4.2 m/s²
= 8.4 N
- We are required to determine the acceleration when the same force is applied to a steel ball with a mass of 2.1 kg.
Mass = 2.1 kg
Force = 8.4 N
But;
Force = mass × acceleration
Acceleration = Force ÷ Mass
= 8.4 N ÷ 2.1 kg
= 4 m/s²
Thus, the acceleration will be 4 m/s²
The rocket would have gone 125 m away in deep space.The speed when it has gone 300 m is 76.7 m/s.
Answer:
The distance the rocket traveled is 125 m. The speed when it has gone 300 m is 76.7 m/s.
Explanation:
According to the equations of motion, if an object is moving with constant acceleration, then the distance travelled by the object with that acceleration and within a specific time can be obtained as
Since the initial velocity is given as u = 0 at t = 0. Then at t = 10 s, the acceleration is given by 2.5 m/.
Thus,
s= 0 + (×2.5×)=125 m.
Thus, the rocket would have gone 125 m away in deep space.
Similarly, if it had gone 300 m then its speed can be determined using the third equation of motion.
Since, here v is unknown and u is known as 0 with a = 2.5 m/.
2× 9.8×300=v²
5880=v²
Thus, the speed v =
So, the speed when it has gone 300 m is 76.7 m/s.
Answer:
-0.9 m/s²
Explanation:
t = Time taken by the hockey puck = 7 seconds
u = Initial velocity of the hockey puck = 13 m/s
v = Final velocity of the hockey puck = 6.7 m/s
a = Acceleration of the hockey puck
Equation of motion
The acceleration of the hockey puck in the seven seconds is -0.9 m/s²
The acceleration due to gravity is not needed to find the acceleration of the puck.
I always thought he was in it