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lisabon 2012 [21]
3 years ago
12

Need help I’ve been stuck on this for awhile

Mathematics
1 answer:
snow_lady [41]3 years ago
3 0

Answer:

x= -35/4

Step-by-step explanation:

Hope it helps you!

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100 points consider the function below -2|x-3|+1 = -2sqrtx-1
Alenkinab [10]

Answer:

D. x = 1.7 or x = 5.7

Step-by-step explanation:

The left side of the equation is graphed in blue. The right side of the equation is graphed in red.

The solution of the equation is the x (and y) that make both equations true.

On the graph these solutions are the points where the two graphs intersect.

Those two points have x values that are positive (and y's that are negative) Only answer D. has x-values that correspond to the x-values of the points of intersection.

3 0
2 years ago
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1) Five hundred tickets were sold for a fundraising dinner. The receipts totaled $3312.50. Adult tickets were $7.50 each and chi
ehidna [41]
Number of adults' tickets (x): $7.50x + $4.00(500 - x) = $3,312.50 $7.50x + $2,000.00 - $4.00x = $3,312.50 $3.50x = $1,312.50 x = 375 
No. of children's tickets (500 - x): = 500 - 375 = 125 
Answer: 375 adults' tickets, 125 children's tickets 
Proof (Receipts totaled $3,312.50): = (375 tickets * $7.50) + (125 tickets * $4.00) = $2,812.50 + $500.00 = $3,312.50
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Line ℓ1 has the equation y=x–5 and line ℓ2 has the equation y=x–1. Find the distance between ℓ1 and ℓ2. round your answer to the
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\ell_1 and \ell_2 are parallel to one another with slope 1. Any line with slope -1 is perpendicular to both of these lines, the simplest being y=-x.

This perpendicular line intersects \ell_1 and \ell_2 at the points (5/2, -5/2) and (1/2, -1/2), respectively.

The distance between \ell_1 and \ell_2 is the same as the distance between these two intersections:

\sqrt{\left(\dfrac52-\dfrac12\right)^2+\left(-\dfrac52+\dfrac12\right)^2}=2\sqrt2\approx\boxed{2.8}

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