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aleksklad [387]
2 years ago
7

What is the answer to Graph y=−x−2.

Mathematics
1 answer:
lukranit [14]2 years ago
4 0

this is the answer is -10 not sure tho

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If x -6 is one factor of x^2 - 10x +24, which is the other factor?
yulyashka [42]
To get the other factor of the expression x² - 10x + 24, we can use long or synthetic division. We are given that the other factor is x - 6, so we can use that as our divisor. Our setup should look something like this:
x² - 10x + 24 ÷ x - 6
Here is the work using polynomial long division:
         <u> x     -4          </u>   
x - 6 | x² - 10x + 24
         <u> </u><span><u>x² - 6x</u>
</span>          0  - 4x + 24
               <span><u>-4x - 24</u>
</span>                          0
We can see that our quotient is x - 4, which would be the other factor of x - 6 to get x² - 10x + 24. The answer to your query is x - 4. Hope this helps and have a phenomenal day!

7 0
3 years ago
What is the Highest.Common.Factor of 18,26and 72​
yanalaym [24]

Answer:

first find the common factors of 18,26 and 72.

18: 1,2,3,6,9,18

26: 1,2,13,26

72: 1,2,3,4,6,8,12,18,24,36,72

next, find the common factors which can divide all numbers: 2

then find the highest factor which can divide all numbers. in this case, we only have one factor which is 2 and that shall be the H.C.F.

4 0
3 years ago
V-3 -5 - 315<br> O True<br> O False
xxMikexx [17]

Answer:

True

Step-by-step explanation:

Why true I had that problem and it was true.

7 0
3 years ago
in a canoe race, a team paddles downstream 480 m in 60 s. The same team makes the trip upstream in 80 s. Find the team's rate in
Vera_Pavlovna [14]
480=60(v+s) 

480=60v+60s

8=v+s

s=8-v...

480=80(v-s)  using s from above we get:

480=80(v-(8-v))

6=v-8+v

6=2v-8

2v=14

v=7, and since s=8-v, s=1

So the rate of the team is 7m/s while the rate of the stream is 1m/s





7 0
3 years ago
Please help me it's urgent
Stels [109]

Step-by-step explanation:

p

2

−2p−100=(−10)

2

−2(−10)−100 [Putting p=−10]

=100+20−100=20.

ᴍᴀʀᴋ ᴀꜱ ʙʀᴀɪɴʟɪᴇᴀꜱᴛ

7 0
3 years ago
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