Step-by-step explanation:
Hey there!!!
Here,
Given, A line passes through point (2,-2) and is perpendicular to the y= 5x+2.
The equation of a straight line passing through point is,

Now, put all values.

It is the 1st equation.
Another equation is;
y = 5x +2........(2nd equation).
Now, Comparing it with y = mx + c, we get;
m2=5
As per the condition of perpendicular lines,
m1×m2= -1
m1 × 5 = -1
Therefore, m2= -1/5.
Keeping the value of m1 in 1st equation.

Simplify them.



Therefore the required equation is x+5y+8= 0.
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
Step-by-step explanation:
We assume you want to compare your expression to the form ...
a(x -h)² +k
1/2(x +1)² +k
The multiplier outside parentheses is ...
a = 1/2
The horizontal offset inside parentheses is ...
-h = 1
h = -1
The vertical offset outside parentheses is ...
k = -3
Answer:
Subtract 2x to bring it to the other side
Step-by-step explanation:
2x+5y=20
-2x. -2x
5y=-2x+20