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Mkey [24]
3 years ago
9

Explain why the "add a decimal and zero rule" work?

Mathematics
1 answer:
Gelneren [198K]3 years ago
8 0

Answer:

he quotient has a remainder of 4.

The quotient has a remainder of 14.

The quotient has no remainder.

The quotient has a remainder of 12.Step-by-step explanation:

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5/8 multiply with 125/125 = 625/1000 -> 0.625
7/10 -> 0.7 
11/20 multiply with 5/5 = 55/100 -> 0.55
21/25 multiply with 4/4 = 84/100 -> 0.84
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The table shows the relationship between r and s, where s is the independent variable.
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3 years ago
4. If 100.0g of nitrogen gas (N2) is reacted with 100.0g of hydrogen gas (H2) to form NH3. What are the limiting and excess reac
alexandr1967 [171]

Nitrogen (N) has a molar mass of about 14.007 g/mol, so you have

100.0 g N₂ = (100.0 g) • (1/28.014 mol/g) ≈ 3.570 mol N₂

Hydrogen (H) has a molar mass of about 1.008 g/mol, so

100.0 g H₂ = (100.0 g) • (1/2.016 mol/g) ≈ 49.60 mol H₂

In the balanced reaction, 1 mole of N₂ reacts with 3 moles of H₂ to make 2 moles of NH₃. We have

3.570 • 3 ≈ 10.71

so the reaction would use up all 3.570 mol N₂ and 10.71 mol H₂ to produce about 7.139 mol NH₃.

(A) H₂ is the excess reactant. There is an excess of 49.60 - 10.71 ≈ 38.89 mol H₂.

(B) N₂ is the limiting reactant. All of the N₂ gets consumed in the reaction.

(C) NH₃ has a molar mass of (14.007 + 3 • 1.008) g/mol = 17.031 g/mol. This reaction would theoretically yield about 7.139 mol NH₃, or

7.139 mol NH₃ = (7.139 mol) • (17.031 g/mol) ≈ 121.6 g NH₃

8 0
3 years ago
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