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steposvetlana [31]
3 years ago
7

Could you please help me. what is -3 -8

Mathematics
2 answers:
Romashka [77]3 years ago
8 0

Answer:

- 11

Step-by-step explanation:

- 3 - 8 \\  =  - 11

<h3>Hope it is helpful.....</h3>
Olegator [25]3 years ago
5 0

Answer:

-11

Step-by-step explanation:

-3-8 can also be written as (-3) + (-8). When the brackets are opened it becomes -3-8.

To determine, whether to add or subtract the two numbers, there is a simple rule:-

1)Minus and Minus makes plus

2)Minus and plus makes Minus

3)plus and Minus makes Minus

4)plus and plus makes plus

Now to determine which sign to be put on the number, there is another rule:-

1) Put the sign of the greater number

Now in this case -3-8.

As you can see there are 2 negative numbers so the first rule is applied and they are added. So that makes 11. The largest number among the 2 is 8 and the sign of 8 is negative and hence our answer is negative that is -11

Hope this helps.

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What’s five and one-half less than 3 times a number ?
notka56 [123]

The equation is 3n - 5 1/2. 5 1/2 = 5.5

3n - 5.5

n could equal 1 so, 3 x 1 - 5.5 = -2.5

3n - 5 1/2 = -2.5


3 0
4 years ago
Verify that each equation is an identity (1 - sin^(2)((x)/(2)))/(1+sin^(2)((x)/(2)))= (1+cosx)/(3-cosX)
Allisa [31]

Answer:

Given that we have;

sin \left (\dfrac{x}{2} \right ) = \sqrt{\dfrac{1 - cos (x)}{2} }

By the application of the law of indices and algebraic process of adding a and subtracting a fraction from a whole number, we have;

\therefore \dfrac{\left ( 1 - sin^2 \left (\dfrac{x}{2} \right ) \right )}{\left ( 1 + sin^2 \left (\dfrac{x}{2} \right ) \right )} =\dfrac{\left ( \dfrac{1 + cos (x)}{2} \right)}{\left (\dfrac{3 - cos (x)}{2} \right ) }  =\dfrac{\left ( 1 + cos (x))}{(3 - cos (x))}

Step-by-step explanation:

An identity is a valid or true equation for all variable values

The given equation is presented as follows;

\dfrac{\left ( 1 - sin^2 \left (\dfrac{x}{2} \right ) \right )}{\left ( 1 + sin^2 \left (\dfrac{x}{2} \right ) \right )} =\dfrac{\left ( 1 + cos (x))}{(3 - cos (x))}

From trigonometric identities, we have;

sin \left (\dfrac{x}{2} \right ) = \sqrt{\dfrac{1 - cos (x)}{2} }

\therefore sin^2 \left (\dfrac{x}{2} \right ) = \dfrac{1 - cos (x)}{2}

1 -  sin^2 \left (\dfrac{x}{2} \right ) = 1 - \dfrac{1 - cos (x)}{2} = \dfrac{2 - (1 - cos (x))}{2} = \dfrac{1 + cos (x))}{2}

1 +  sin^2 \left (\dfrac{x}{2} \right ) = 1 + \dfrac{1 - cos (x)}{2} = \dfrac{2 + 1 - cos (x))}{2} = \dfrac{3 - cos (x))}{2}

\therefore \dfrac{\left ( 1 - sin^2 \left (\dfrac{x}{2} \right ) \right )}{\left ( 1 + sin^2 \left (\dfrac{x}{2} \right ) \right )} =\dfrac{\left ( \dfrac{1 + cos (x)}{2} \right)}{\left (\dfrac{3 - cos (x)}{2} \right ) }  =\dfrac{\left ( 1 + cos (x))}{(3 - cos (x))}

\therefore \dfrac{\left ( 1 - sin^2 \left (\dfrac{x}{2} \right ) \right )}{\left ( 1 + sin^2 \left (\dfrac{x}{2} \right ) \right )} =\dfrac{\left ( 1 + cos (x))}{(3 - cos (x))}

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Answer:

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Step-by-step explanation:

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Please help me with this question
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Answer:

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Step-by-step explanation:

Mia is correct

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When n = 4, 3n + 3 = 3*4 + 3 = 12 +3 = 15

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Mnenie [13.5K]

Answer:


Step-by-step explanation:

Please find attachment for step by step explanation.

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