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3 years ago

So I was doing a hooda math escape game, and forgot how to do these. Can you help me?

Mathematics

2 answers:

Alika [10]3 years ago

5 0

to find the radius you divide the circumference by 2pi

area is pi times radius to the 2nd power

Maslowich3 years ago

5 0

Answer:

The formula for area equals pi times the radius squared, R stands for the radius measurement of the circle. So the formula is area equals pi R squared.

Step-by-step explanation:

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-4x-2y=-12<br> solve the system of equations

Blababa [14]

Um there needs to be another equation

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3 years ago

Bryce tried to solve an equation step by step.

Aloiza [94]

$$c=\frac{1}{3}$

Solution:

Given equation is $\frac{8}{3}=3c+\frac{5}{3}$ .

To solve the equation by step by step.

Step 1: Given

$\frac{8}{3}=3c+\frac{5}{3}$

Step 2: Combine like terms together.

Plus symbol changed to minus when the term goes from right to left (or) left to right of the equal sign.

$\frac{8}{3}-\frac{5}{3}=3c$

Step 3: Subtract the fractions in the left side.

$\frac{3}{3}=3c$

⇒ $1=3c$$

Step 4: Divide both side of the equation by 3, we get

$\frac{1}{3} =\frac{3c}{3}$

$\frac{1}{3} =c$

Hence, the answer is $c=\frac{1}{3}$ .

8 0

3 years ago

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The following data points represent the number of classes that each teacher at Broxin High School teaches.

nika2105 [10]

Answer:

Step-by-step explanation:

4 0

3 years ago

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Expand (x-3)(x-8) to form a quadratic expression

AlladinOne [14]

Answer:

x^2 - 11x + 24

Step-by-step explanation:

Foil the equation

x^2 - 3x - 8x + 24

x^2 - 11x + 24

8 0

3 years ago

The average daily temperature, t, in degrees fahrenheit for a city as a function of the month of the year, m, can be modeled by

Vikentia [17]

The answer will be t = $sin((m.\frac{\pi}{6})+55)$ average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

<h3>What is temperature?</h3>

Temperature is the degree or intensity of heat present in a substance or object, especially as expressed according to a comparative scale and shown by a thermometer or perceived by touch.

<h3>TO SOLVE:</h3>

$35cos(\frac{\pi}{6(m+3)}+55)\\\\35 cos(\frac{\pi m}{6} + 55 + \frac{\pi}{2})\\$

suppose $x = m.\frac{\pi}{6}+55$ and $\frac{\pi}{2} = 90$ degree

We know, cos(x+90°) = - sin(X)

⇒ $cos((m.\frac{\pi}{6})+55+90degree)$ degree = - $sin((m.\frac{\pi}{6})+55)$

⇒ t = $sin((m.\frac{\pi}{6})+55)$

Hence the answer will be t = $sin((m.\frac{\pi}{6})+55)$ average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

To learn more visit:

brainly.com/question/27441712

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3 0

2 years ago