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Vesna [10]
3 years ago
8

So I was doing a hooda math escape game, and forgot how to do these. Can you help me?

Mathematics
2 answers:
Alika [10]3 years ago
5 0

to find the radius you divide the circumference by 2pi

area is pi times radius to the 2nd power

Maslowich3 years ago
5 0

Answer:

The formula for area equals pi times the radius squared, R stands for the radius measurement of the circle. So the formula is area equals pi R squared.

Step-by-step explanation:

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-4x-2y=-12<br> solve the system of equations
Blababa [14]
Um there needs to be another equation
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3 years ago
Bryce tried to solve an equation step by step.
Aloiza [94]

$c=\frac{1}{3}

Solution:

Given equation is \frac{8}{3}=3c+\frac{5}{3}.

To solve the equation by step by step.

Step 1: Given

$\frac{8}{3}=3c+\frac{5}{3}$

Step 2: Combine like terms together.

Plus symbol changed to minus when the term goes from right to left (or) left to right of the equal sign.

$\frac{8}{3}-\frac{5}{3}=3c$

Step 3: Subtract the fractions in the left side.

$\frac{3}{3}=3c$

⇒ 1=3c$

Step 4: Divide both side of the equation by 3, we get

$\frac{1}{3} =\frac{3c}{3}$

$\frac{1}{3} =c$

Hence, the answer is c=\frac{1}{3}.

8 0
3 years ago
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The following data points represent the number of classes that each teacher at Broxin High School teaches.
nika2105 [10]

Answer:

3

Step-by-step explanation:

4 0
3 years ago
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Expand (x-3)(x-8) to form a quadratic expression
AlladinOne [14]

Answer:

x^2 - 11x + 24

Step-by-step explanation:

Foil the equation

x^2 - 3x - 8x + 24

x^2 - 11x + 24

8 0
3 years ago
The average daily temperature, t, in degrees fahrenheit for a city as a function of the month of the year, m, can be modeled by
Vikentia [17]

The answer will be t = sin((m.\frac{\pi}{6})+55) average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

<h3>What is temperature?</h3>

Temperature is the degree or intensity of heat present in a substance or object, especially as expressed according to a comparative scale and shown by a thermometer or perceived by touch.

<h3>TO SOLVE:</h3>

35cos(\frac{\pi}{6(m+3)}+55)\\\\35 cos(\frac{\pi m}{6} + 55 + \frac{\pi}{2})\\

suppose x = m.\frac{\pi}{6}+55 and \frac{\pi}{2} = 90 degree

We know, cos(x+90°) = - sin(X)

⇒ cos((m.\frac{\pi}{6})+55+90degree)degree = -sin((m.\frac{\pi}{6})+55)

⇒ t = sin((m.\frac{\pi}{6})+55)

Hence the answer will be t = sin((m.\frac{\pi}{6})+55) average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

To learn more visit:

brainly.com/question/27441712

#SPJ4

3 0
2 years ago
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