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Reptile [31]
3 years ago
14

Solve 8x = 1 quick plz

Mathematics
1 answer:
Ulleksa [173]3 years ago
4 0

Answer:

x = 1/8 = 0.125

Step-by-step explanation: Add 1 to both sides of the equation :

8x = 1

Divide both sides of the equation by 8:

x = 1/8 = 0.125

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At the end of the summer, Caitlin had saved $120 from her summer job. This was her initial deposit into a new savings account at
Vera_Pavlovna [14]
<span>Let x = represent the number of weeks of deposits
A = 120 + 5x the account balance after x weeks
The account balance is directly proportional to the number of weeks of deposits if:
A/x = constant
(120 + 5x)/x = 120/x + 5 is not a constant
For example:
After 1 week there will be: 120 + 1*5 = $125 on the account
After 2 week there will be: 120 + 2*5 = $130 on the account
After 3 week there will be: 120 + 3*5 = $135 on the account
But 125/1 <> 130/2 <> 135/3
The account balance is not proportional to the number of weeks of deposits.</span>
8 0
2 years ago
Perform the indicated operation​ and, if​ possible simplify<br> 2/3-1/7
Fiesta28 [93]
11/21 would be the answer
3 0
3 years ago
Please help thx a bunch
kirza4 [7]
A.
2/3A=-24
time both sides by 3/2
A=-72/2
A=-36

B.
20=-B/0.2
times both sides by 0.2
4=-B
times -1
-4=B


distance between 2 points x and y is |x-y|

so
distance between A and B is distance between -4 and -72 or
|-72-(-4)|=|-72+4|=|-68|=68
the distance is 68
4 0
2 years ago
Jerry had 45 tickets for games at a carnival.he used 1/3 of the tickets to play ball-toss game. He used 2/5 of the tickets to pl
MrRa [10]
45 / 3 = 15
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30 / 5 = 6
6 x 2 = 12
30 - 12 = 18
The answer is D:18
7 0
2 years ago
What is the equation for a circle with a center at (-2,-4) that passes through the point (3,8)?
Margarita [4]
Check the picture below.

so, the center of the circle is the midpoint of that diametrical segment, and half that length is the radius.

\bf ~~~~~~~~~~~~\textit{middle point of 2 points }&#10;\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~ -2 &,& -4~) &#10;%  (c,d)&#10;&&(~ 3 &,& 8~)&#10;\end{array}\qquad&#10;%   coordinates of midpoint &#10;\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)&#10;\\\\\\&#10;\left( \cfrac{3-2}{2}~~,~~\cfrac{8-4}{2} \right)\implies \left( \frac{1}{2}~,~2 \right)\impliedby center

\bf ~~~~~~~~~~~~\textit{distance between 2 points}&#10;\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~ -2 &,& -4~) &#10;%  (c,d)&#10;&&(~ 3 &,& 8~)&#10;\end{array}~~~ &#10;%  distance value&#10;d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}&#10;\\\\\\&#10;d=\sqrt{[3-(-2)]^2+[8-(-4)]^2}\implies d=\sqrt{(3+2)^2+(8+4)^2}&#10;\\\\\\&#10;d=\sqrt{25+144}\implies d=\sqrt{169}\implies d=13\qquad\qquad \qquad  \stackrel{radius}{\frac{13}{2}}

\bf \textit{equation of a circle}\\\\ &#10;(x- h)^2+(y- k)^2= r^2&#10;\qquad &#10;center~~(\stackrel{\frac{1}{2}}{ h},\stackrel{2}{ k})\qquad \qquad &#10;radius=\stackrel{\frac{13}{2}}{ r}&#10;\\\\\\&#10;\left( x-\frac{1}{2} \right)^2+(y-2)^2=\left( \frac{13}{2} \right)^2\implies \left( x-\frac{1}{2} \right)^2+(y-2)^2=\frac{169}{4}

3 0
3 years ago
Read 2 more answers
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