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Annette [7]
3 years ago
13

uma wanted to have a test average of 85%. On her first 7 tests she averaged 83% on her tests. what does she need to get on her 8

th test to have an overall average of 85%
Mathematics
1 answer:
UkoKoshka [18]3 years ago
7 0

Answer:

99%

Step-by-step explanation:

83% * 7 tests = 581

\frac{581+x}{8} =85

solve for x (the percentage needed on the 8th test)

x = 99%

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What is the sum of all the positive integers from <br> √<br> 24<br> to <br> √<br> 102<br> ?
Eva8 [605]

Answer:

The sum of all positive integers is

5 + 6 + 7 + 8 + 9 + 10

              = <em>45</em>

Step-by-step explanation:

Because \sqrt{24} = 4.89 and \sqrt{102} = 10.09

So positive numbers between 4.9 and 10.09 are

 <em>5+6+7+8+9+10 = 45</em>

<em />

<em>Brainliest will be appreciated.</em>

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3 years ago
Https://prnt.sc/zozycx<br> va rog rapid !
stellarik [79]

Answer:

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Step-by-step explanation: im confused

5 0
3 years ago
I NEED HELP ASAP!!!!!
lara31 [8.8K]

Answer:

W = 2.5d + 62

Step-by-step explanation:

The calf weighed 62 pounds when they were born. This gives us a base of 62 pounds - the calf cannot weigh less than 62 pounds and it does on day 0. On each day , the calf gains 2.5 pounds. We can times the number to days by 2.5 to get the gain from day 0. We can add these two values together to get the total current weight of the calf.

3 0
3 years ago
Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the
kodGreya [7K]

Answer:

  • p=0.7103 (4-game series)
  • p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters  n=4, p=0.6:

P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\  i=4,5,6,7

#We find probabilities for the different values of i:

P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659

Hence, probability of the stronger team winning overall is:

=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103

#Define Y as the random variable for winning 2/3 games.:

P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

8 0
3 years ago
Claire has received scores of 85,82, and 75 on her algebra tests. what score must she receive on the fourth test to have an over
Nina [5.8K]
Fourth test mark should be 86

85 + 82 + 75 + 86 = 328
328 divide by 4 (as there are four tests) = 82
8 0
4 years ago
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