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sleet_krkn [62]
3 years ago
9

Angles ABC and angles CBD fom a linear pair. if mABC = 6x-12 and mCBD=x+31, find the mABD

Mathematics
1 answer:
Stella [2.4K]3 years ago
7 0

x=43/5, you have to set them equal to each other because they are a linear pair


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Simplify (ignore my garbage camera quality ....)
monitta

Answer:

C. 3

Step-by-step explanation:

Given expression is:

({3^{\frac{1}{7}})^7

We know that the rules of exponents are used to solve these kind of questions.

When there is exponent on exponent like in this question 1/7 has an exponent of 7 , the exponents are multiplied.

So,

=3^{(7*\frac{1}{7} )}

The 7's will be cancelled out and remaining power will be 1

=3^1\\=3

Hence, option C is correct ..

5 0
3 years ago
Read 2 more answers
Which expression is equivalent to √900f^6/100g^4
krek1111 [17]

Answer:

A

Step-by-step explanation:

c and d cannot be since the answer to sqrt((900f^6)/(100g^4)) is 3f³/g²

and not 30f something.

the best answer I see is correct is a.

6 0
3 years ago
( 7x + 1/2) + ( 7x - 7 and 1/2) Simplify
pishuonlain [190]

Answer:

The answer will be 7(2x - 1)

Step-by-step explanation:

1) Convert 7 and 1/2 to improper fraction. Use this rule: a b/c = ac + b/c

7x +  \frac{1}{2}  + 7x -  \frac{7 \times 2 + 1}{2}

2) Simplify 7 × 2 to 14 .

7x +  \frac{1}{2}  + 7x  -  \frac{14 + 1}{2}

3) Simplify 14 + 1 to 15.

7x +  \frac{1}{2}  + 7x -  \frac{15}{2}

4) Collect like terms.

(7x + 7x) + ( \frac{1}{2}  -  \frac{15}{2} )

5) simplify.

14x - 7

6) Factor out the common term 7.

7(2x - 1)

Therefor, the answer is 7( 2x - 1 ).

7 0
3 years ago
What is the common denominator of (5/x^2-4) - (2/x+2) in the complex fraction (2/x-2) - (3/x^2-4)/(5/x^2-4) - (2/x+2)
PIT_PIT [208]

9514 1404 393

Answer:

  • common denominator: (x² -4)
  • simplified complex fraction: (2x +1)/(9 -2x)

Step-by-step explanation:

It is helpful to remember the factoring of the difference of squares:

  a² -b² = (a -b)(a +b)

__

Your denominator of (x² -4) factors as (x -2)(x +2). You will note that one of these factors is the same as the denominator in the other fraction.

It looks like you want to simplify ...

  \dfrac{\left(\dfrac{2}{x-2}-\dfrac{3}{x^2-4}\right)}{\left(\dfrac{5}{x^2-4}-\dfrac{2}{x+2}\right)}=\dfrac{\left(\dfrac{2(x+2)}{(x-2)(x+2)}-\dfrac{3}{(x-2)(x+2)}\right)}{\left(\dfrac{5}{(x-2)(x+2)}-\dfrac{2(x-2)}{(x-2)(x+2)}\right)}\\\\=\dfrac{2(x+2)-3}{5-2(x-2)}=\boxed{\dfrac{2x+1}{9-2x}}

3 0
3 years ago
Rewrite the following equation in exponential form.<br> log 49(7) = 1/2
asambeis [7]
It would be log7squared(7)
4 0
4 years ago
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