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barxatty [35]
3 years ago
11

Please answer and explain cause I a bit lost…

Mathematics
1 answer:
kiruha [24]3 years ago
4 0
X= -1 and x=2, the roots of the graph is where ever the graph touches the x axis.
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SOMEONE PLEASE HELP!<br>Set up an inequality showing that the radicand cannot be negative.
Stolb23 [73]

Answer:

3t-9 >= 0

Step-by-step explanation:

Original function f(t)= square root 3t-9

There cannot be a negative in the radicand therefore 3t-9 cannot equal a negative number.  

6 0
4 years ago
Read 2 more answers
Solve the equation.<br> x² =96<br><br> A 4/6<br><br> B 16/6<br><br> C 9<br><br> D 9,-9
alexgriva [62]

Answer:

x = ± 4\sqrt{6}

Step-by-step explanation:

Given

x² = 96 ( take the square root of both sides )

x = ± \sqrt{96} = ±  \sqrt{16(6)} = \sqrt{16} × \sqrt{6} = ± 4\sqrt{6}

3 0
4 years ago
A tablet is on sale for 30% off. the regular price is $185. how much money will you save?
Burka [1]

Answer:

185×30÷100=55.5

HERES YOUR answer

8 0
3 years ago
Write an equation of a line parallel to y=10x+6 and going through point (2,-4)
nadya68 [22]

Answer:

Y= 10x-24 would be parralel to y=10x+6

Step-by-step explanation:

well a parralel line has to have the same slope and a different y-intercept.

To find the y-intercept the x has to be exactly 0.

So we have (2,-4)

The slope is 10/1 which is 10y and 1 x which in an ordered park would be Add 1 x and add 10 y. But we’re trying to get x to be 0 to find the y-intercept.

So subtract 1 x and subtract 10y

2-1=1

-4-10=-14

(1, -14)

1-1=0

-14-10=-24

(0, -24)

THe y-intercept is -24 and w have the slope since its the same thing So

y=10x-24 is the equation

7 0
3 years ago
Triangle DEF has vertices D(−4, 1), E(2, 3), and F(2, 1) and is dilated by a factor of 3 using the point (1, 1) as the point of
CaHeK987 [17]

Answer: D'(-14,1);\ E'(4,7);\ F'(4,1)

Step-by-step explanation:

Since the center of dilation is not at the origin, we can use the following formula in order to find the coordinates of the vertices of the triangle D'E'F':

D_{O,k}(x,y)=(k(x-a)+a, k(y-b)+b)

Where "O" is the center of dilation at (a,b) and "k" is the scale factor.

In this case you can identify that:

(a,b)=(1,1)\\k=3

Therefore, susbtituting values into the formula shown above, you get that the coordinates ot the resulting triangle D'E'F, are the following:

Vertex D' → (3(-4-1)+1,\ 3(1-1)+1)=(-14,1)

Vertex E' → (3(2-1)+1,\ 3(3-1)+1)=(4,7)

Vertex F' → (3(2-1)+1,\ 3(1-1)+1)=(4,1)

6 0
4 years ago
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