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Airida [17]
3 years ago
5

What's the slope of the line ? And explain please

Mathematics
1 answer:
tia_tia [17]3 years ago
5 0
You take the difference between any two y and divide by the difference in the corresponding x. The number should be the same always for a straight line. That's your slope. A fancy way of writing it is dy/dx

so: (10-2)/(3-1) = 8/2 = 4 (using the first two points)
or: (26-2)/(7-1) = 24/6 = 4 (using the first and the last)

try it out for other combinations. The answer is 4 every time.
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Use Euler's method with each of the following step sizes to estimate the value of y(0.4), where y is the solution of the initial
sergey [27]

Answer:

h=0.4--> 15

h=0.2 --> 14.06

h=0.1 --> 13.71

Step-by-step explanation:

This is a numerical solution using Euler's method. Euler's method enables us to numerically approch a solution with a suitable  step size. As the step size gets smaller, the approximation will be more accurate. Euler's method is as the following.

y_{i+1}=y_{i}+h*y_{first derivation}

Here, h is the step size. The reason why first derivation used here is to make an appriximation with using the rate of increase or decrease. As the step size is smaller, the icreases or decreases are followed more accurately. Now, let's solve the question:

for h= 0.4:

y(0.4)=y(0)+0.4*y'

The trick here is y' is equal to y, thus we can write that y'=y(0.4) and our starting point y(0) is given as 9 in the question and the equation becomes:

y(0.4)=9+0.4*y(0.4) and this is easy to solve.By replacing y(0.4) functions to be at the same side of the equation, we get:

0.6*y(0.4)=9 and by solving this equation, y(0.4) is found to be 15.

for h=0.2:

This will be similar to the previous question, but since the step size is 0.2, we will first calculate y(0.2) and then y(0.4).

y(0.2)=y(0)+0.2*y(0.2) and y(0) is 9.

0.8*y(0.2)=9 and y(0.2)=11.25. Now, we will replace this value into the next iteration o the formula istead of y(0). The equation is like:

y(0.4)=y(0.2)+0.2*y(0.4) and y(0.4) is found to be 14.06.

for h=0.1:

This is also similar to the above solutions but will be longer and have 4 iterations.

first iteration: y(0.1)=9+0.1*y(0.1) --> y(0.1)=10

second iteration: y(0.2)=y(0.1)+0.1*y(0.2) --> y(0.2)=11.11

third iteration: y(0.3)=y(0.2)+0.1*y(0.3) --> y(0.3)=12.34

fourth iteration: y(0.4)=y(0.3)+0.1*y(0.4) --> y(0.4)=13.71

As the step size gets smaller, the answer also gets smaller and more accurate. With even smaller step sizes, there will be a better approximation. However, in case you have more complex equations or smaller step sizes, it is recommended to use a computer software to make an approximation.

6 0
3 years ago
what is true about every rotation? the image and pre-image are congruent. the image is larger than the pre-image. the image over
Rudiy27
I think the correct answer from the choices listed above is the first option. The statement that is true for every rotation would be that the image and pre-image are congruent. A<span>ll the rest deals with changing the rotated shape not a constant. Hope this helps.</span>
4 0
3 years ago
Read 2 more answers
Which best describes a fraction?
MrRa [10]

Answer:

A

Step-by-step explanation:

5 0
3 years ago
Solve 8(m - 5 ) = 48
Art [367]

Answer

1)8(m -5 ) = 48 \\ 8m - 40 = 48 \\ 8m = 48 + 40 \\ 8m = 88 \\  \frac{8m}{8}  =  \frac{88}{8}  \\ m = 11

2)x + 7 = 13 \\ x = 13 - 7 \\ x = 6

3)3h - 5 = 12 \\ 3h = 12 + 5 \\ 3h = 17 \\  \frac{3h}{3}  =  \frac{17}{3}  \\ h = 5 \frac{2}{3}

Hope this helps you.

Let me know if you have any other questions :-):-)

4 0
2 years ago
Read 2 more answers
Find the approximate perimeter of ABC plotted below.
maksim [4K]

Answer:

B. 21.2

Step-by-step explanation:

Perimeter of ∆ABC = AB + BC + AC

A(-4, 1)

B(-2, 3)

C(3, -4)

✔️Distance between A(-4, 1) and B(-2, 3):

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AB = \sqrt{(-2 - (-4))^2 + (3 - 1)^2} = \sqrt{(2)^2 + (2)^2)}

AB = \sqrt{4 + 4}

AB = \sqrt{16}

AB = 4 units

✔️Distance between B(-2, 3) and C(3, -4):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

BC = \sqrt{(3 - (-2))^2 + (-4 - 3)^2} = \sqrt{(5)^2 + (-7)^2)}

BC = \sqrt{25 + 49}

BC = \sqrt{74}

BC = 8.6 units (nearest tenth)

✔️Distance between A(-4, 1) and C(3, -4):

AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AC = \sqrt{(3 - (-4))^2 + (-4 - 1)^2} = \sqrt{(7)^2 + (-5)^2)}

AC = \sqrt{47 + 25}

AC = \sqrt{74}

AC = 8.6 units (nearest tenth)

Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units

8 0
3 years ago
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