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Phoenix [80]
3 years ago
11

PLZ I REALLY NEED THIS RIGHT AWAY!!! I’ll GIVE YOU BRAINLIST!!!

Mathematics
1 answer:
bearhunter [10]3 years ago
8 0
They are all being multiplied by 4
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Y = 4x + 2<br> on a graph
miss Akunina [59]
Answer
X= -0.5
Y=2
If you need me to explain I can.

4 0
3 years ago
Anna has been adding $30 to her savings account every month. Which model could represent the money in Anna’s savings account (y)
RSB [31]

Y=30x.
Whatever the number of months is you times by 30, the amount she added each month. If she had started with a certain amount you would add that to the equation. Y is the total money in the account.
7 0
3 years ago
Read 2 more answers
Plz help me with my geometry asap 50 pts and brainliest NO SCAMMING OR I WILL REPORT
bearhunter [10]

Step-by-step explanation:

1. You already got the first step, where D is the midpoint of AC and AB is congruent to BC, since it's given.

2. AD will be congruent to DC, via the definition of a midpoint (a midpoint is the middle point of a line segment, and it splits the segment into two congruent parts)

3. BD is equal to BD, via reflexive property. ( It's a shared side between the two triangles)

4. that means that ΔADB ≅ΔCDB via SSS rule.

5. ∠ABD ≅∠CDB by CPCTC (corresponding parts of congruent triangles are congruent)

Hope this helps! :)

4 0
2 years ago
Read 2 more answers
Help me please I need help?
liubo4ka [24]
I think it is D

I am not sure but this is what I think it is
4 0
3 years ago
Read 2 more answers
cho tứ giác ABCD. Gọi M,N,P,Q là trung điểm của các cạnh AB, CD, AD, BC. Chứng minh rằng vecto MP = vecto QN, vecto MQ = vecto P
Dmitriy789 [7]

Answer:

Step-by-step explanation:

Xét tam giác DAB có: P là trung điểm AD, M là trung điểm AB

=> MP là đường trung bình của tam giác DAB => MP//BD và MP=\frac{1}{2}BD  (1)

Xét tam giác DBC có: N là trung điểm DC, Q là trung điểm BC

=> QN là đường trung bình của tam giác DBC => QN//BD và QN=\frac{1}{2}BD  (2)

Từ (1) và (2) => vecto MP song song cùng chiều với vecto QN

và độ dài MP = độ dài QN = \frac{1}{2}BD

=> vecto MP = vecto QN

Tương tự xét các tam giác DAC và tam giác ABC => vecto MQ = vecto PN

4 0
2 years ago
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