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11Alexandr11 [23.1K]
3 years ago
12

Combustion of 1 mole of an organic compound requires 4 moles of oxygen. The formula of the organic compound is a) CH4 b) C2H c)

C3H4 d) C2H4​
Chemistry
1 answer:
Nina [5.8K]3 years ago
7 0

Answer:

your answer will be A hope ur help and mark me brainlist

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Does Catalysts increase the rate of chemical reactions. true or false
anastassius [24]
True.

A catalyst is a substancr that increases the rate of a chemical reaction without itself undergoing any permanent chemical change.

6 0
3 years ago
Explain what a mole of copper (Cu) atoms and a mole of Sulfur Dioxide (SO2) molecules have in common.
evablogger [386]

Answer:

The amount of molecules → 6.02×10²³

Explanation:

Avogadro Number (NA) is the amount of particles that are contained in 1 mol of anything.

It does not matter the mass of compounds, or molecules, 1 mol has 6.02×10²³ particles, the same number for every compound.

1 mol of H₂O that weighs 18 grams has 6.02×10²³ molecules

1 mol of sucrose, that weighs 342 g has 6.02×10²³ molecules

Generally, the NA  is the number of atoms in 12 grams of the carbon-12 isotope.

6 0
3 years ago
Calculate the temperature of a 0.50 mol sample of a gas at 0.987 atm and a volume of 12 L.
Aleonysh [2.5K]

Answer: 15.5^0C

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 0.987 atm

V = Volume of gas = 12 L

n = number of moles = 0.50

R = gas constant =0.0821Latm/Kmol

T =temperature =  ?

T=\frac{PV}{nR}

T=\frac{0.987atm\times 12L}{0.0820 L atm/K mol\times 0.50mol}=288.5K=(288.5-273)^0C=15.5^0C

Thus the temperature of a 0.50 mol sample of a gas at 0.987 atm and a volume of 12 L is 15.5^0C

8 0
3 years ago
Helpppppppppppppppppppppppppppppppppp
dimulka [17.4K]
These could all go either way, hardness and other special properties are what I'm guessing would be the most accurate in determining the kind of material.
luster, cleavage, streak, and color can all be affected by other factors. but I guess cleavage would also be accurate. so I guess hardness special properties and cleavage would be the most reliable.
5 0
4 years ago
A sample of an unknown compound was decomposed and found to be composed of 1.36 mol oxygen, 4.10 mol hydrogen, and 2.05 mol carb
AfilCa [17]

We are given the number of moles:

O = 1.36 mol

H = 4.10 mol

C = 2.05 mol

 

To get the empirical formula, first divide everything by the smallest number of moles = 1.36 mol. So that:

O = 1 mol

H = 3 mol

C = 1.5 mol

 

Next step is to multiply everything by a number such that all will be a whole number. In this case, multiply by 2 to get a whole number for C, so that:

O = 2 mol

H = 6 mol

C = 3 mol

 

Therefore the empirical formula of the compound is:

C3H6O2

8 0
4 years ago
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