Explanation:
The given data is as follows.
Flow of chlorine (Q) = 
Amount of liter present per day is as follows.

It is given that dosage of chlorine will be as follows.
10 mg/l =
kg/l
Therefore, total chlorine requirement is as follows.
Total chlorine requirement =
kg/day
= 100 kg/day
Thus, we can conclude that the kilograms of chlorine used daily at the given water treatment plant is 100 kg/day.
28 degrees below freezing would be 4 degrees
The expression for the Ka for the given acid is:
Ka = [H2P2O7^2-] [H3O+] /[H3P2O7^2-]
<span>Ka is the acid dissociation constant or the acidity constant. It is a measure of the acid strength when in solution. It is an equilibrium constant for the dissociation of the acid.</span>