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frozen [14]
3 years ago
15

Does Catalysts increase the rate of chemical reactions. true or false

Chemistry
1 answer:
anastassius [24]3 years ago
6 0
True.

A catalyst is a substancr that increases the rate of a chemical reaction without itself undergoing any permanent chemical change.

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I need to know the weighted average please!
maria [59]

Answer:

63.5456 amu

Explanation:

0.6917*62.9296+0.3083*64.9278= 63.5456\ amu

8 0
3 years ago
HELP PLEASE!!!!The graph below compares the volume occupied by 100 g of liquid water and 100 g of water vapor.
soldier1979 [14.2K]

Particles are farther apart in gases so substance X is water vapor

Explanation:

The best statement that fits the two described substances is that particles are farther apart in gases so substance X is water vapor. For a give mass of substance, gases occupies more volume.  

Gases do not have specific volumes, occupy space randomly and fills whichever container they are found in.  

Liquids on the other hand like solids have specific volume because their particles are very close together.  

Particles of gases are random and their molecules are far apart.  

Learn more:  

states of matter  brainly.com/question/10954198

#learnwithBrainly

3 0
3 years ago
Vanillin is the compound containing carbon, hydrogen, and oxygen that gives vanilla beans their distinctive flavor. The combusti
nignag [31]
<span>70.4 mg CO2 x 1.0 g /1000 mg x 1 mole CO2/ 44 gCO2 x 1 mole C/1 mole CO2 = 0.0016 moles C 14.4 mg H2O x 1.0 g/1000 mg x 1 mole H2O/18 g H2O x 2 moles H/ 1 mole H2O = 0.0016 moles O molar mass of C=12 g/mole molar mass of H=1 g/mole 0.0016 moles C x 12 g C/ 1 mole C = 0.0192 g C or 19.2 mg C 0.00156 moles H x 1 g H/1 mole H = 0.00156 g H or 1.56 mg H mg O= 30.4 mg vanillin - 19.2 mg C – 1.56 mg H = 9.64 mg O molar mass of O=16 g/mole 9.64 mg O x 1 g/1000 mg x 1 mole O/16.0 g = 0.000602 C.0016 H.0016 O.000602; divide all the moles by the smallest value of0.000602 C2.66H2.66O1 is the empirical formula; to obtain whole numbers multiply by 3 3[C2.66H2.66O1] = C8H8O3 above formula weight: 8(C) + 8(H) + 3(O) = 8(12) + 8(1) + 3(16) = 152 amu The empirical formula weight and the molecular formula weight are the same . Molecular formula is C8H8O3.</span>
7 0
3 years ago
How many moles of dipyrithione contain 8.2 x 10^24 atoms of N
Pani-rosa [81]
Dipyrithione is a chemical with formula, C₁₀H₈N₂O₂S₂. This means that each molecule of the substance has two (2) atoms of nitrogen. By using the dimensional analysis and Avogadro's number, equal to 6.022 x 10²³, we calculate for the answer as shown below.

    n = (8.2 x 10²⁴ atoms N)(1 molecule dipyrithione/ 2 atoms of N)(1 mole dipyrithione/ 6.022 x 10²³ molecules dipyrithione)

Simplifying,
  n = 6.8 moles dipyrithione

<em>ANSWER: 6.8 moles</em>
4 0
3 years ago
Mg + 2 AgNO₃ → Mg(NO₃)₂ + 2 Ag How many grams of magnesium nitrate, Mg(NO₃)₂, are formed when 9.87 moles of silver nitrate, AgNO
Aleksandr-060686 [28]

Mass of Magnesium nitrate formed : 731.86 g

<h3>Further explanation</h3>

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

Reaction

Mg + 2AgNO₃ → Mg(NO₃)₂ + 2 Ag

moles of silver nitrate, AgNO₃ = 9.87

mole ratio AgNO₃ : Mg(NO₃)₂ = 2 : 1, so mol Mg(NO₃)₂ :

\tt \dfrac{1}{2}\times 9.87=4.935

mass of Mg(NO₃)₂(MW=148,3 g/mol) :

\tt mass=mol\times MW\\\\mass=4.935\times 148,3\\\\mass=731.86~g

4 0
3 years ago
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