mathematical symbol for period is "T"
Answer:
2.448 * 10^-5M
Explanation:
To calculate the concentration of the solution, we apply the Beer Lambert law equation.
That is A = £LC
Where £ represents the molar extinction coefficient.
We identify the values as follows:
A = absorbance = 0.735
L = cell length = 1.30
£ = 23100
c = concentration = ?
Rearranging the equation, c = A/£L
c = 0.735/(23,100 * 1.3)
c = 2.448 * 10^-5 M
Answer:
A. C₃H₄N
Explanation:
- Firstly, we need to calculate the no. of moles of C, H, and N using the relation:
<em>no. of moles = mass/molar mass.</em>
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∴ no. of moles of C = mass/molar mass = (90.0 g)/(12.0 g/mol) = 7.5 mol.
∴ no. of moles of H = mass/molar mass = (11.0 g)/(1.0 g/mol) = 11.0 mol.
∴ no. of moles of N = mass/molar mass = (35.0 g)/(14.0 g/mol) = 2.5 mol.
- We should get the mole ratio of each atom by dividing by the lowest no. of moles (2.5 mol of N).
∴ the mole ratio of C: H: N = (7.5 mol/2.5 mol): (11.0 mol/2.5 mol): (2.5 mol/2.5 mol) = (3: 4.4: 1) ≅ (3: 4: 1).
- So, the empirical formula is: A. C₃H₄N.
Using PV=nRT or the ideal gas equation, we substitute n= 15.0 moles of gas, V= 3.00L, R equal to 0.0821 L atm/ mol K and T= 296.55 K and get P equal to 121.73 atm. The Van der waals equation is (P + n^2a/V^2)*(V-nb) = nRT. Substituting a=2.300L2⋅atm/mol2 and b=0.0430 L/mol, P is equal to 97.57 atm. The difference is <span>121.73 atm- 97.57 atm equal to 24.16 atm.</span>
B, C, D are compounds, while A and E are just element stand-alones.
