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2 years ago

Can anyone help? please

Mathematics

1 answer:

kirill115 [55]2 years ago

5 0

Step-by-step explanation:

BCD = 180- 100 = 80

the opposite angles of a parallelogram are of equal measure

SO DAB = X = 80

The sum of all parallelogram angles = 360

360 - 160 = 200

200 equals the measure of angle ADC + ABC

ABC = ADC

200 = 2ABC

ABC = 100

ADB = DBC = 30

Y = 100 - 30 = 70

another way to find y is using the rule that says that the sum of the triangle ADB angles = 180

180 = 80 + 30 + y

y = 70

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Gelneren [198K]

I'll abbreviate the definite integral with the notation,

$I(f(x),a,b)=\int_a^bf(x)\,\mathrm dx$

We're given

$I(f,1,8)=9$
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$I(g,1,5)=3$

Recall that the definite integral is additive on the interval $[a,b]$ , meaning for some $c\in[a,b]$ we have

$I(f,a,b)=I(f,a,c)+I(f,c,b)$

The definite integral is also linear in the sense that

$I(kf+\ell g,a,b)=kIf(a,b)+\ell I(g,a,b)$

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Also, if $a\ge b$ , then

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a. $I(2f,1,5)=2I(f,1,5)=2(I(f,1,8)-I(f,5,8))=2(9-4)=\boxed{10}$

b. $I(f-g,1,8)=I(f,1,8)-I(g,1,8)=9-5=\boxed{4}$

c. $I(f-g,1,5)=I(f,1,5)-I(g,1,5)=\dfrac{I(2f,1,5)}2-I(g,1,5)=10-3=\boxed{7}$

d. $I(g-f,5,8)=I(g,5,8)-I(f,5,8)=(I(g,1,8)-I(g,1,5))-I(f,5,8)=(5-3)-4=\boxed{-2}$

e. $I(7g,5,8)=7I(g,5,8)=7(5-3)=\boxed{14}$

f. $I(3f,5,1)=3I(f,5,1)=-3I(f,1,5)=-\dfrac32I(2f,1,5)=-\dfrac32(10)=\boxed{-15}$

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2 years ago

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Answer:

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Subtract 10 from both sides of the equation to isolate 14b:

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Divide 14 on both sides of the equation to solve for b:

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Can anyone help? please ​

Can anyone help? please