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Alchen [17]
3 years ago
12

Please help im stressing :(((( (what is Danielle mistake in this problem )

Mathematics
1 answer:
statuscvo [17]3 years ago
7 0

Answer:

Daniel's Mistake was that she didnt add all the sides

Step-by-step explanation:

She only added the right side of the triangle, and the right and bottom sides of the square. She is missing the left of the triangle, which is another 6x-4, and the left side of the square, which is 12x +3.

Using these sides the answer should look like this,

set up your problem

1) (6x-4)*2 + (12x+3)*2 + (14x+13)

multiply your 2's in

2) (12x-8) + (24x+6) + (14x+13)

simplify

3) 50x + 11 is your answer

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-0.84 ÷ 2.1 = -0.4

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20 points!! Solve this system of lineal equations.separate the x- and y- values with a comma
Zielflug [23.3K]
Solve the following system:{12 x = 54 - 6 y | (equation 1)-17 x = -6 y - 62 | (equation 2)
Express the system in standard form:{12 x + 6 y = 54 | (equation 1)-(17 x) + 6 y = -62 | (equation 2)
Swap equation 1 with equation 2:{-(17 x) + 6 y = -62 | (equation 1)12 x + 6 y = 54 | (equation 2)
Add 12/17 × (equation 1) to equation 2:{-(17 x) + 6 y = -62 | (equation 1)0 x+(174 y)/17 = 174/17 | (equation 2)
Multiply equation 2 by 17/174:{-(17 x) + 6 y = -62 | (equation 1)0 x+y = 1 | (equation 2)
Subtract 6 × (equation 2) from equation 1:{-(17 x)+0 y = -68 | (equation 1)0 x+y = 1 | (equation 2)
Divide equation 1 by -17:{x+0 y = 4 | (equation 1)0 x+y = 1 | (equation 2)
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Please note the { are supposed to span over both equations but it interfaces doesn't  allow it. Please see attachment for clarification.

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3 years ago
The terminal point of Dis ( 1/2,3/2). What is cos 0?
nydimaria [60]

Answer:

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