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Veseljchak [2.6K]
3 years ago
12

A particular country has 55 total states. If the areas of all 55 states are added and the sum is divided by 55​, the result is 1

91 comma 435 square kilometers. Determine whether this result is a statistic or a parameter.
Mathematics
1 answer:
zhuklara [117]3 years ago
4 0

Answer:

It's a parameter.

Step-by-step explanation:

It is a parameter because you have consider the entire population, in this case the states, you have all the data of them (The areas). this would be an statistic if you cosulted a few of them instead.

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Determine which function has the greatest rate of change as x approaches infinity
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I honestly don’t know what the answer is but I’m sorry
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3 years ago
−10x+5=−6x−35 ooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo
Zarrin [17]

Answer:

x=10

Step-by-step explanation:

Add 6x to both sides.

−4x+5=−35

Subtract 5 from both sides.

−4x=−40  

Divide both sides by -4.

\frac{-4x}{-4}=\frac{-40}{-4}

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Read 2 more answers
The length of the base of a rectangular prism is 9
Tatiana [17]

Answer:

The volume of the prism is <u>320 15/16 inches³</u>.

Step-by-step explanation:

Given:

The length of the base of a rectangular prism is 9 7/8.

The width of the prism is 8 1/8.

And the height is 4 inches.

Now, to find the volume of the prism.

(Length) <em> l = 9 7/8 = 79/8 inches.</em>

(Width)  <em> w = 8 1/8 = 65/8 inches</em>.

(Height)  <em>h = 4 inches</em>.

So, by putting the formula to get the volume:

Volume = w×h×l.

Volume=\frac{65}{8}\times 4\times \frac{79}{8}

Volume=320\frac{15}{16}

<em>Volume = 320 15/16 inches³.</em>

Therefore, the volume of the prism is 320 15/16 inches³.

7 0
3 years ago
A genetic experiment involving peas yielded one sample of offspring consisting of 420 green peas and 174 yellow peas. Use a 0.01
slavikrds [6]

Answer:

a) z=\frac{0.293 -0.23}{\sqrt{\frac{0.23(1-0.23)}{594}}}=3.649  

b) For this case we need to find a critical value that accumulates \alpha/2 of the area on each tail, we know that \alpha=0.01, so then \alpha/2 =0.005, using the normal standard table or excel we see that:

z_{crit}= \pm 2.58

Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis at 1% of significance.

Step-by-step explanation:

Data given and notation

n=420+174=594 represent the random sample taken

X=174 represent the number of yellow peas

\hat p=\frac{174}{594}=0.293 estimated proportion of yellow peas

p_o=0.23 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of yellow peas is 0.23:  

Null hypothesis:p=0.23  

Alternative hypothesis:p \neq 0.23  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.293 -0.23}{\sqrt{\frac{0.23(1-0.23)}{594}}}=3.649  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z>3.649)=0.00026  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis.

b) Critical value

For this case we need to find a critical value that accumulates \alpha/2 of the area on each tail, we know that \alpha=0.01, so then \alpha/2 =0.005, using the normal standard table or excel we see that:

z_{crit}= \pm 2.58

Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis at 1% of significance.

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I don't know if this is the right one but i hope this helps. this is how i learned it. 
step 1=get variables on one side oof the equal sign by using inverse operation (add or subtract smaller variable) 
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step 3: isolate the variable using inverse operation (multiply or divide) 
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3 years ago
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