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jekas [21]
3 years ago
7

Is negative 5 a rational number or an irrational number (Pleasee help me)

Mathematics
1 answer:
solong [7]3 years ago
8 0

Answer:

Negative five is in fact a rational number.

Step-by-step explanation:

Rational numbers can either be negative or positive. An irrational number would be pi (3.14159 etc.)

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Can you give an example of equations when you are given the constant of proportionality?
stealth61 [152]

Identifying the Constant of Proportionality. ... The constant of proportionality is the ratio between two directly proportional quantities. In our tomato example, that ratio is $3.00/2, which equals $1.50. Two quantities are directly proportional when they increase and decrease at the same rate.


6 0
3 years ago
The value of 8 in 5.18 is <br> of the value of 8 in 5.81.
Cloud [144]

Answer: This is false.

Step-by-step explanation:

The value of 8 in 5.18 is 8 Hundredths, the value of 8 in 5.81 is 8 Tenths.

6 0
3 years ago
What is the justification for each step in solving the inequality?
Alik [6]
75x+35≥7(11x+9)+475x+35≥7(11x+9)+4

75x+35≥77x+63+475x+35≥77x+63+4        [expand all blackets]

75x+35≥77x+6775x+35≥77x+67                [collect like terms]

−2x+35≥67−2x+35≥67 −2x≥32−2x≥32       [subtract 77x through]

x≤−16x≤−16                                                [subtract 35 through and divide through by 2]
4 0
3 years ago
According to the norms established for a reading comprehension test, eighth-graders should average 83.2 with a standard deviatio
joja [24]

Answer:

t=\frac{86.7-83.2}{\frac{8.6}{\sqrt{45}}}=2.73    

p_v =P(t_{44}>2.73)=0.0045    

If we compare the p value and a significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the population mean is signficantly higher than 83.2 at 1% of significance.

Step-by-step explanation:

Data given and notation    

\bar X=86.7 represent the average life for the sample    

s=8.6 represent the population standard deviation    

n=45 sample size    

\mu_o =83.2 represent the value that we want to test    

\alpha=0.01 represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

State the null and alternative hypotheses.    

We need to apply a two tailed  test.  

What are H0 and Ha for this study?    

Null hypothesis:  \mu \leq 83.2  

Alternative hypothesis :\mu > 83.2  

Compute the test statistic  

The statistic for this case is given by:  

t=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic    

We can replace in formula (1) the info given like this:    

t=\frac{86.7-83.2}{\frac{8.6}{\sqrt{45}}}=2.73    

Give the appropriate conclusion for the test  

First we need to calculate the degrees of freedom given by:

df=n-1=45-1=44

Since is a one side right tailed test the p value would be:    

p_v =P(t_{44}>2.73)=0.0045    

Conclusion    

If we compare the p value and a significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the population mean is signficantly higher than 83.2 at 1% of significance.

8 0
3 years ago
Each side of a square is increasing at a rate of 6cm/s. At what rate is the area of the square increasing when the area of the s
diamong [38]
Area of a square = length²
A = x²
16 = x²; x = 4
dA/dx = 2x cm²/s
dx/dt = 6 cm/s
Using chain rule:
dA/dt = dA/dx * dx/dt
dA/dt = 2x * 6
dA/dt = 12x
At x = 4,
dA/dt = 12(4) = 48 cm²/s
7 0
3 years ago
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