Add 11 + 16. Plug in 11 into b-2 since b equals eleven. You should now have 11+16+11-2. Do the same thing and plug in 16 for c and 11 for b for c-b. Your solution will now be 11+16+11-2+16-11.
(-3)(8+-10)
(-3) • ( -2)
which equals 6
Answer:
B
Step-by-step explanation:
![\sqrt[4]{2x^2} *\sqrt[4]{2x^3} =(2x^2)^{1/4}*(2x^3)^{1/4}\\= 2^{1/4}*(x^2)^{1/4} *2^{1/4} * (x^3)^{1/4}\\](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2x%5E2%7D%20%2A%5Csqrt%5B4%5D%7B2x%5E3%7D%20%3D%282x%5E2%29%5E%7B1%2F4%7D%2A%282x%5E3%29%5E%7B1%2F4%7D%5C%5C%3D%202%5E%7B1%2F4%7D%2A%28x%5E2%29%5E%7B1%2F4%7D%20%2A2%5E%7B1%2F4%7D%20%2A%20%28x%5E3%29%5E%7B1%2F4%7D%5C%5C)
combine like terms

these steps use exponent laws
a few key ones i used:
(x^y^z) = x^(y*z)
x^y * x^z = x^(y+z)
let me know if you have any questions!
Answer:
-7
Step-by-step explanation:
The answer is -27 . sorry if it’s wrong homie