You just started a new job with a salary of $37,440 a year ($18 an hour).
With an expected rent payment of 25% - 30% of your gross monthly income, find 5 apartments
that you can choose from in any city or town in The United States. Your move in date is on June
12th. 2022.
Answer the following questions:
1. What is your rental range per month (up to 30% of your gross monthly income)
2. What amenities do you want/need (# of bedrooms/ bathrooms, washer/dryer, pets
allowed etc....)
3. List your 5 apartments, with cost of rent.
4. Of the 5, which one did you choose? Why?
5. What would be the total move in cost (application fee, security deposit, prorated rent)?
Answer:
Equation of tangent plane to given parametric equation is:

Step-by-step explanation:
Given equation
---(1)
Normal vector tangent to plane is:


Normal vector tangent to plane is given by:
![r_{u} \times r_{v} =det\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\cos(v)&sin(v)&0\\-usin(v)&ucos(v)&1\end{array}\right]](https://tex.z-dn.net/?f=r_%7Bu%7D%20%5Ctimes%20r_%7Bv%7D%20%3Ddet%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Chat%7Bi%7D%26%5Chat%7Bj%7D%26%5Chat%7Bk%7D%5C%5Ccos%28v%29%26sin%28v%29%260%5C%5C-usin%28v%29%26ucos%28v%29%261%5Cend%7Barray%7D%5Cright%5D)
Expanding with first row

at u=5, v =π/3
---(2)
at u=5, v =π/3 (1) becomes,



From above eq coordinates of r₀ can be found as:

From (2) coordinates of normal vector can be found as
Equation of tangent line can be found as:

Answer:
25,000
Step-by-step explanation:
100,000*25%= 25,000
Answer:
y = 9x + 18
where y is the weight and x is the age
Explanation:
Assume that the age is x and the weight is y.
We are given that:
At age of 16, Logan was 162 pounds. Therefore, point on the line is (16,162)
At age of 20, Logan was 198 pounds. Therefore, point on the line is (20,198)
The general form of the linear equation is:
y = mx + c
where m is the slope and c is the y-intercept
1- getting the slope:
slope (m) = (y2-y1) / (x2-x1)
m = (198-162) / (20-16) = 9
The equation now becomes:
y = 9x + c
2- getting the y-intercept:
The two given points belong to the required line. This means that each of them satisfies the equation of the line.
So, to get the y-intercept, we will substitute with one of the points in the equation and solve for c.
I will use point (16,162) as follows:
y = mx + c
162 = 9(16) + c
162 = 144 + c
c = 162 - 144 = 18
Therefore, the equation becomes:
y = 9x + 18
Hope this helps :)