Jullian fully simplifies this polynomial and then writes it in standard form. 4x^2y^2-2y^4-8xy^3+9x^3y+6y^4-2xy^3-3x^4+x^2y^2 if
jullian wrote the last term as -3x^4, which must be the first term of his polynomial in standard form?
A. 4y^4
B. 6y^4
C. -2xy^3
D. -10xy^3
1 answer:
Answer:

Step-by-step explanation:
He added
, so you need to include it, the new expression now being

You need to simplify the polynomial first (combine all like terms) and it should become

The only option that actually exists are A and D, the answer would be D though because the letters that come first in the alphabet have more priority
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The discriminant is b^2 -4ac
a = 1
b = -2
c = 4
discriminant = 4 -4 * 1 * 4 =
4 -16 =
-12
I get MINUS 12 as the answer but that isn't one of the choices.
D 64 if this is right please give me brainlist
2x-4=3x-11 so add 4 to 11 and that’s -7 then subtract 2x from 3x so that’s 1x so 1x divides by -7 equals -7 so x=-7
Did you mean 36/12? If so the answer would be 3/1 or 3.
The v means the square root I hope this helps