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pychu [463]
3 years ago
8

Jullian fully simplifies this polynomial and then writes it in standard form. 4x^2y^2-2y^4-8xy^3+9x^3y+6y^4-2xy^3-3x^4+x^2y^2 if

jullian wrote the last term as -3x^4, which must be the first term of his polynomial in standard form?
A. 4y^4
B. 6y^4
C. -2xy^3
D. -10xy^3
Mathematics
1 answer:
eimsori [14]3 years ago
7 0

Answer:

-10xy^{3}

Step-by-step explanation:

He added -3x^4, so you need to include it, the new expression now being

4x^2y^2-2y^4-8xy^3+9x^3y+6y^4-2xy^3-3x^4+x^2y^2-3x^4

You need to simplify the polynomial first (combine all like terms) and it should become

5x^2y^2+4y^4-10xy^3+9x^3y-6x^4

The only option that actually exists are A and D, the answer would be D though because the letters that come first in the alphabet have more priority

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