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pychu [463]
3 years ago
8

Jullian fully simplifies this polynomial and then writes it in standard form. 4x^2y^2-2y^4-8xy^3+9x^3y+6y^4-2xy^3-3x^4+x^2y^2 if

jullian wrote the last term as -3x^4, which must be the first term of his polynomial in standard form?
A. 4y^4
B. 6y^4
C. -2xy^3
D. -10xy^3
Mathematics
1 answer:
eimsori [14]3 years ago
7 0

Answer:

-10xy^{3}

Step-by-step explanation:

He added -3x^4, so you need to include it, the new expression now being

4x^2y^2-2y^4-8xy^3+9x^3y+6y^4-2xy^3-3x^4+x^2y^2-3x^4

You need to simplify the polynomial first (combine all like terms) and it should become

5x^2y^2+4y^4-10xy^3+9x^3y-6x^4

The only option that actually exists are A and D, the answer would be D though because the letters that come first in the alphabet have more priority

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Multiplying -15 by 60 yields -900, so the amount of water in the pool changes by -900 gallons in one hour.
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In a cross-country run organized by a school, the students who completed the run
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Read 2 more answers
Find the tangent of ∠I.
Nady [450]

Answer:

tanI = \frac{\sqrt{70} }{5}

Step-by-step explanation:

We require to calculate GH using Pythagoras' identity in the right triangle.

GH² + GI² = HI²

GH² + 5² = (\sqrt{95} )²

GH² + 25 = 95 ( subtract 25 from both sides )

GH² = 70 ( take square root of both sides )

GH = \sqrt{70}

Then

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4 0
2 years ago
A bag contains 11 numbered chips inside. Two chips are labeled 1, three are labelled 2, and six are labelled 3. Let the random v
Dima020 [189]

Answer: 2.36

Step-by-step explanation:

Using the μ=∑[x⋅P(X=x)

U will need to do

2/11 because you have 2 labeled 1

3/11 because you have 3 labeled 2

6/11 because you have 6 labeled 3

Then you will do:

1 x 2/11 = 0.18

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3 x 6/11 = 1.63

Then add them all together to find the μ

0.18 + 0.55 + 1.63 = 2.36

Hope that helps, plz put a good rating

4 0
3 years ago
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