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Pepsi [2]
2 years ago
9

Write the repeating decimal 0.63333 as afraction

Mathematics
1 answer:
sergeinik [125]2 years ago
5 0

Step-by-step explanation:

just count off the positions after the decimal point.

they go with decreasing negative exponents of ten.

the first position is 1/10.

the second 1/100.

the third 1/1000.

the fourth 1/10000

the fifth 1/100000

and that is how we can easily convert such decimals into fractions.

0.63333 = 63333 / 100000

or were you looking for the infinite decimal ?

that would be 1.9/3 = 19/10 / 3 = 19/30

I found this by simply suspecting that there is a division by 3 involved (due to the 3333333 repeating pattern).

so, by multiplying 0.63333 by 3 we get 1.9.

1.9 = 19/10

and then dividing by 3 gives us 19/30

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What is the vertical asymptote of this function?
liraira [26]

Answer:

D

Step-by-step explanation:

If y = log x is the basic function, let's see the transformation rule(s):

Then,

1. y = log (x-a) is the original shifted a units to the right.

2. y = log x + b is the original shifted b units up

Hence, from the equation, we can say that this graph is:

** 2 units shifted right (with respect to original), and

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<u><em>only, left or right shift affects vertical asymptotes.</em></u>

Since, the graph of y = log x has x = 0 as the vertical asymptote and the transformed graph is shifted 2 units right (to x = 2), x = 2 is the new vertical asymptote.

Answer choice D is right.

7 0
3 years ago
What is the simplified answer to this problem 12 &gt; -3x + 6
Verdich [7]

In this question, you're simplifying the inequality by solving for x.

Solve for x:

12 > -3x + 6

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Answer:

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The volume in this case would be:

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Step-by-step explanation:

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