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erik [133]
2 years ago
9

A. 2 B. -2 C. 1/2 D. -1/2

Mathematics
1 answer:
allsm [11]2 years ago
7 0

Rate of change is the slope.

The slope is the change in Y over the change in X:

Slope = (5- -3) / (2 - -2)

Slope = 8/4

Slope = 2

Answer: A.2

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Solve the system of equations -5y+4x= 49 7y+2x= -23 Find X and Y<br> Will mark Brainlest
grigory [225]

<em>Answer:</em>

<em>y = - 5 ; x = 6</em>

<em>Step-by-step explanation:</em>

<em>-5y+4x= 49</em>

<em>7y+2x= -23 | × - 2</em>

<em />

<em>-5y+4x= 49</em>

<em>-14y - 4x = 46</em>

<em>___________ +</em>

<em>- 5y - 14y + 4x - 4x = 49 + 46</em>

<em>- 19y = 95 | × - 1</em>

<em>19y = - 95</em>

<em>y = - 95 : 19</em>

<em>y = - 5</em>

<em />

<em>- 5(-5) + 4x = 49</em>

<em>25 + 4x = 49</em>

<em>4x = 49 - 25</em>

<em>4x = 24</em>

<em>x = 24 : 4</em>

<em>x = 6</em>

8 0
3 years ago
Answer the following questions.
SOVA2 [1]

Answer:

43

Step-by-step explanation:


5 0
3 years ago
2.The number of grams A of a certain radioactive substance present at time, in yearsfrom the present, t is given by the formulaA
professor190 [17]

Answer:

Given that,

The number of grams A of a certain radioactive substance present at time, in years

from the present, t is given by the formula

A=45e^{-0.0045(t)}

a) To find the initial amount of this substance

At t=0, we get

A=45e^{-0.0045(0)}A=45e^0

We know that e^0=1 ( anything to the power zero is 1)

we get,

A=45

The initial amount of the substance is 45 grams

b)To find thehalf-life of this substance

To find t when the substance becames half the amount.

A=45/2

Substitute this we get,

\frac{45}{2}=45e^{-0.0045(t)}

\frac{1}{2}=e^{-0.0045(t)}

Taking natural logarithm on both sides we get,

\ln (\frac{1}{2})=-0.0045(t)^{}(-1)\ln (\frac{1}{2})=0.0045(t)\ln (\frac{1}{2})^{-1}=0.0045(t)\ln (2)=0.0045(t)0.6931=0.0045(t)t=\frac{0.6931}{0.0045}t=154.02

Half-life of this substance is 154.02

c) To find the amount of substance will be present around in 2500 years

Put t=2500

we get,

A=45e^{-0.0045(2500)}A=45e^{-11.25}A=45\times0.000013=0.000585A=0.000585

The amount of substance will be present around in 2500 years is 0.000585 grams

4 0
1 year ago
Find the value of x.
pogonyaev

1st image:

20 (20 + x) = 40^2

400 + 20x = 1600

20x = 1200

   x = 60

---------------

2nd image:

5 * x = 10 * 6

5x = 60

 x = 12


4 0
3 years ago
Evaluate x-2 for x = -3.
Vadim26 [7]
X-2 for x=-3
-3-2=-5, add dem negatives
8 0
3 years ago
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