Answer: 16 in
Explanation:
PQ/QR = PT/TS
PQ/4 = 12/3
PQ x 3 = 12 x 4 (cross multiply)
PQ x 3 = 48
PQ = 48/3
PQ = 16
Given:
Total number of students = 27
Students who play basketball = 7
Student who play baseball = 18
Students who play neither sports = 7
To find:
The probability the student chosen at randomly from the class plays both basketball and base ball.
Solution:
Let the following events,
A : Student plays basketball
B : Student plays baseball
U : Union set or all students.
Then according to given information,




We know that,



Now,





It means, the number of students who play both sports is 5.
The probability the student chosen at randomly from the class plays both basketball and base ball is


Therefore, the required probability is
.
The number is 125 and the equation is 0.8x = 100
Step-by-step explanation:
80% of x is equal to 100.
Write an equation that shows the relationship of 80%, x, and 100
80% = 0.8
0.8x = 100
x = 100/0.8
x = 125
The number is 125 and the equation is 0.8x = 100
no beacuse when distributed it will be:
16x + 72 - 2
16x + 70