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2 years ago

Solve for c:c5-3= -15PLEASE SHOW WORK!!!

Mathematics

1 answer:

White raven [17]2 years ago

7 0

Answer:

c = -2.4 or -12/5

Step-by-step explanation:

5c - 3 = -15

First we need to add 3 to both sides so,

5c - 3 + 3 = -15 + 3

so we can now solve it

5c = -12 then we divide 5 by both sides

c = -12 / 5

c = -2.4

The fraction form is -12/5

The decimal form is -2.4

Hope this helps!!

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Three potential employees took an aptitude test. Each person took a different version of the test. The scores are reported below

BARSIC [14]

Answer:

Due to the higher Z-score, Demetria should be offered the job.

Step-by-step explanation:

Z-score:

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

Whichever applicant had grade with the highest z-score should be offered the job.

Demetria got a score of 85.1; this version has a mean of 61.1 and a standard deviation of 12.

For Demetria, we have $X = 85.1, \mu = 61.1, \sigma = 12$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{85.1 - 61.1}{12}$

$Z = 2$

Vincent got a score of 299.2; this version has a mean of 264 and a standard deviation of 22.

For Vincent, we have $X = 299.2, \mu = 264, \sigma = 22$ .

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{299.2 - 264}{22}$

$Z = 1.6$

Tobias got a score of 7.26; this version has a mean of 7.1 and a standard deviation of 0.4.

For Tobias, we have $X = 7.26, \mu = 7.1, \sigma = 0.4$ .

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{7.26 - 7.1}{0.4}$

$Z = 0.4$

Due to the higher Z-score, Demetria should be offered the job.

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3 years ago

How many integers between 360 and 630 are there such that they have odd number of divisors?

Kryger [21]

Answer:

Step-by-step explanation:

Concept to Know: "A number is a perfect square if and only if it has odd number of positive divisors "

Find all the squared values that lies between 360 and 630

360< 19², 20², 21², 22², 23², 24², 25² < 630

19², 20², 21², 22², 23², 24², and 25² are all the squared values that lies between 360 and 630. There are seven of those squared numbers so the answer is 7.

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2 years ago

Find the sum of the finite geometric series. 4 20 100 ... 312,500 the sum of the geometric series is .

AnnZ [28]

What is the 9th term of the geometric sequence 4, -20, 100, ...
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2 years ago

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Nataliya [291]

Answer:

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Step-by-step explanation:

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if 1L is equal to 0.26

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2 years ago

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3 years ago